Question

我的学说查询显然在checkmate::assert_numeric(1, names = "named") #> Error in withCallingHandlers({: Assertion on '1' failed: Vector must be named.返回了错误的类型，但是我不明白为什么。它说返回数组；这就是我所期望的...

控制器：

getResult()

存储库

public function checkbrute($username, $email ) {

   $repository = $this->getDoctrine()->getRepository(LoginAttempts::class);

   $now = time();
   $valid_attempts = $now - (2 * 60 * 60);

   $attempts = $repository->emailLoginAttempts($email, $valid_attempts);

   return sizeof($attempts);

}

错误：

    public function emailLoginAttempts($email, $valid_attempts): ?LoginAttempts
{
    return $this->createQueryBuilder('l')
        ->select('l.time')
        ->andWhere('l.email = :val')
        ->andWhere('l.time > :val2')
        ->setParameter('val', $email)
        ->setParameter('val2', $valid_attempts)
        ->getQuery()
        ->getResult() //ERROR HERE
    ;
}

实体：

Return value of App\Repository\LoginAttemptsRepository::emailLoginAttempts() must be an instance of App\Entity\LoginAttempts or null, array returned

Answer 1

您的emailLoginAttempts实际上是返回LoginAttempts的数组，因此，此PHP给您错误。解决方法取决于您的实际逻辑：

如果您需要从LoginAttempts接收单个emailLoginAttempts实例-您需要将getResult()替换为getOneOrNullResult()。
如果您需要接收包含多个LoginAttempts实例的数组-您需要更新方法签名以返回数组：public function emailLoginAttempts($email, $valid_attempts): array并添加PHPDoc @return LoginAttempts[]，这样类型信息就不会丢失。

Symfony 4 / Doctrine查询：返回值必须是的实例

1 个答案: