具有使用OkHttp实现的异步REST API客户端,效果很好。 出于好奇,尝试将其转换为WebClient,观察到奇怪的行为。
WebClient配置就是这样:
webClient = WebClient.builder()
.defaultHeaders(headers -> headers.add(HttpHeaders.CONTENT_TYPE,
org.springframework.http.MediaType.APPLICATION_JSON_VALUE))
.clientConnector(new ReactorClientHttpConnector(builder -> builder
.option(ChannelOption.CONNECT_TIMEOUT_MILLIS, timeout)))
.build();
请求代码:
void getTokenWithWebClient(Consumer<Try<String>> callback) {
webClient.post()
.uri(url)
.syncBody(new MyRequest())
.retrieve()
.onStatus(status -> status.value() != HttpStatus.OK.value(),
rs -> rs.bodyToMono(String.class).map(body -> new IOException(String.format(
"Response HTTP code is different from 200: %s, body: '%s'", rs.statusCode(), body))))
.bodyToMono(MyResponse.class)
.subscribe(rs -> callback.accept(Try.of(() -> validateResponse(Option.of(rs)))),
ex -> callback.accept(Try.failure(ex)));
}
在单元测试中,作为参数传递给此方法的回调完成了Future,我在上面等待。 因此,当我运行在IDEA中进行测试,并且请求导致响应的主体为空(内容长度:0)时,subscribe()中的lambda永远不会执行-使用println调试进行了验证。 / p>
但是,当我调试相同的测试时,即使未设置任何断点,它也会按预期完成,并根据结果调用lambda。
我确实在日志中看到了这一点:
[reactor-http-nio-4] DEBUG reactor.ipc.netty.http.client.HttpClientOperations - [id: 0xeffaded6, L:/127.0.0.1:49265 - R:localhost/127.0.0.1:58522] Received last HTTP packet
[reactor-http-nio-4] DEBUG reactor.ipc.netty.http.client.HttpClient - [id: 0xeffaded6, L:/127.0.0.1:49265 - R:localhost/127.0.0.1:58522] USER_EVENT: [Handler Terminated]
[reactor-http-nio-4] DEBUG reactor.ipc.netty.channel.ChannelOperationsHandler - [id: 0xeffaded6, L:/127.0.0.1:49265 - R:localhost/127.0.0.1:58522] Disposing context reactor.ipc.netty.channel.PooledClientContextHandler@3547abe3
[reactor-http-nio-4] DEBUG reactor.ipc.netty.channel.PooledClientContextHandler - Releasing channel: [id: 0xeffaded6, L:/127.0.0.1:49265 - R:localhost/127.0.0.1:58522]
[reactor-http-nio-4] DEBUG reactor.ipc.netty.resources.DefaultPoolResources - Released [id: 0xeffaded6, L:/127.0.0.1:49265 - R:localhost/127.0.0.1:58522], now 0 active connections
[reactor-http-nio-4] DEBUG reactor.ipc.netty.http.client.HttpClient - [id: 0xeffaded6, L:/127.0.0.1:49265 - R:localhost/127.0.0.1:58522] READ COMPLETE
[reactor-http-nio-4] DEBUG reactor.ipc.netty.http.client.HttpClient - [id: 0xeffaded6, L:/127.0.0.1:49265 - R:localhost/127.0.0.1:58522] READ COMPLETE
[reactor-http-nio-4] DEBUG reactor.ipc.netty.http.client.HttpClient - [id: 0xeffaded6, L:/127.0.0.1:49265 ! R:localhost/127.0.0.1:58522] CLOSE
[reactor-http-nio-4] DEBUG reactor.ipc.netty.http.client.HttpClient - [id: 0xeffaded6, L:/127.0.0.1:49265 ! R:localhost/127.0.0.1:58522] INACTIVE
[reactor-http-nio-4] DEBUG reactor.ipc.netty.http.client.HttpClient - [id: 0xeffaded6, L:/127.0.0.1:49265 ! R:localhost/127.0.0.1:58522] UNREGISTERED
但是后来我的错误的Mono卡在了某个地方。
在Windows 7,Oracle JDK8 x64,IDEA 2018上运行此命令。 选项/尝试是vavr类(io.vavr:vavr),与这种情况无关。 对于单元测试,我使用Ratpack模拟有问题的REST API。
尝试使用exchange()而不是restore()并在没有onStatus()的情况下检查subscribe()lambda中的状态码-结果相同。
有什么想法吗?
答案 0 :(得分:0)
长话短说,rs.bodyToMono(String.class).defaultIfEmpty("")
挽救了一天