Question

在我的应用程序中，我有以下型号

fee.rb

class Fee < ActiveRecord::Base
  acts_as_paranoid
  belongs_to :instructor_student
  belongs_to :instructor
  has_many :fee_payment_notifications, dependent: :destroy
end

fee_payment_notifications.rb

class FeePaymentNotification < ActiveRecord::Base
  belongs_to :fee
end

instructor.rb

class Instructor < ActiveRecord::Base
  has_many :fees
  has_many :fee_payment_notifications, through: :fees
end

我想通过费用支付通知进行内部加入费用当我直接在费用支付通知中使用费用加入通知时，出现以下错误

@instructor.fee_payment_notifications.joins(:fee)

PG::UndefinedTable: ERROR:  invalid reference to FROM-clause entry for table "fees"
LINE 1: ..."."id" = "fee_payment_notifications"."fee_id" AND "fees"."de...
                                                             ^
HINT:  Perhaps you meant to reference the table alias "fees_fee_payment_notifications".
: SELECT "fee_payment_notifications".* FROM "fee_payment_notifications" INNER JOIN "fees" "fees_fee_payment_notifications" ON "fees_fee_payment_notifications"."id" = "fee_payment_notifications"."fee_id" AND "fees"."deleted_at" IS NULL INNER JOIN "fees" ON "fee_payment_notifications"."fee_id" = "fees"."id" WHERE "fees"."deleted_at" IS NULL AND "fees"."instructor_id" = $1

可能是因为Deleted_at字段所致，所以我要使用以下查询进行手动联接

@instructor.fee_payment_notifications.select("fee_payment_notifications.* from fee_payment_notifications AS fp INNER JOIN fees as f ON fp.fee_id = f.id")

它给我下面的错误

PG :: SyntaxError：错误：“ FROM”或附近的语法错误第1行：... ns作为fp内部联接费用，作为f ON fp.fee_id = f.id FROM“ fee _... ^ ：从fee_payment_notifications AS中选择fee_payment_notifications。*作为fp INNER JOIN费用，如f ON fp.fee_id = f.id FROM“ fee_payment_notifications” INNER JOIN“ fees” ON“ fee_payment_notifications”。“ fee_id” =“ fees”。“ id” WHERE“费用“。” deleted_at“为NULL，”费用“。” instructor_id“ = $ 1 =>＃

我应该如何编写查询以手动加入费用和费用支付通知？

Answer 1

这不是查询问题。这是因为paranoia宝石。因此，您应该在模型中编写该代码。

acts_as_paranoid without_default_scope: true

请检查this链接。您可以找到添加默认范围。

宝石偏执狂-PG :: SyntaxError：错误：“ FROM”或附近的语法错误

1 个答案: