Question

我有一个来自weather.com的json文件。如何从“今天”列中获取数据并通过php显示。

public Record insertData(
        Configuration configuration, Table<? extends Record> table, Map<TableField<? extends Record, ?>, Object> map
    )
    {
        return DSL.using(configuration)
            .insertInto(table)
            .set(map)
            .returning()
            .fetchOne();
    }

Answer 1

您可以使用array_column仅获取值。
然后，如果您使用array_combine和array_keys，则也可以获取密钥。

$arr = json_decode($json, true);
$todayvalues = array_column($arr["vt1dailyforecast"]["day"], 0);
$todaykeys = array_keys($arr["vt1dailyforecast"]["day"]);
$today = array_combine($todaykeys, $todayvalues);

输出

array(20) {
  ["dayPartName"]=>
  string(5) "Today"
  ["precipPct"]=>
  int(10)
  ["precipAmt"]=>
  float(0)
  ["precipType"]=>
  string(4) "rain"
  ["temperature"]=>
  int(96)
  ["uvIndex"]=>
  int(10)
  ["uvDescription"]=>
  string(9) "Very High"
  ["icon"]=>
  int(30)
  ["iconExtended"]=>
  int(3000)
  ["phrase"]=>
  string(13) "Partly Cloudy"
  ["narrative"]=>
  string(50) "Partly cloudy. High 96F. Winds light and variable."
  ["cloudPct"]=>
  int(36)
  ["windDirCompass"]=>
  string(1) "S"
  ["windDirDegrees"]=>
  int(177)
  ["windSpeed"]=>
  int(5)
  ["humidityPct"]=>
  int(57)
  ["qualifier"]=>
  NULL
  ["snowRange"]=>
  string(0) ""
  ["thunderEnum"]=>
  int(0)
  ["thunderEnumPhrase"]=>
  string(10) "No thunder"
}

https://3v4l.org/7PXan

如何从json weather.com文件中获取数据并在php中显示结果

1 个答案: