Question

我需要使用Python自动化Excel文件，问题是Excel中包含宏，当单击宏按钮时，它会弹出一个弹出窗口：

Macro screenshot

弹出消息框本身具有一个按钮，我必须单击该按钮才能继续。我已经尝试过使用Python使用Win32com和Win32 API库，但是在文档中找不到任何解决方案。

我的代码如下：

    ms_excel_app = win32.gencache.EnsureDispatch('Excel.Application')
    ms_excel_app.Visible = True
    ms_excel_app.DisplayAlerts = False

    template_file = r"C:\Templates_for_test\macro_test.xlsm"


    ms_excel_file =ms_excel_app.Workbooks.Open(template_file)
    ms_excel_file.DisplayAlerts = False
    excel_sheet = ms_excel_file.ActiveSheet
    # Opening a template file
    ms_excel_file = ms_excel_app.Workbooks.Open(template_file)

    spread_sheet = ms_excel_file.ActiveSheet

    # Click on 'Current date and time' macro button
    ms_excel_app.Application.Run("Sheet1.CommandButton1_Click")
    # TODO  verify verify timestamp and click ok- popup appears verify date and time format : dd/mm/yyyy hh:mm:ss
    timestamp_message = time.strftime("%d/%m/%Y %H:%M:%S")

我要做的是在屏幕快照中标识弹出窗口，然后单击“确定”按钮

Answer 1

有点晚了，因为我遇到了同样的情况，所以只发布一个解决方案。

该消息框使 Excel 应用程序卡住并相应地阻止了您的主进程。所以，一个通用的解决方案：

启动一个子线程来收听消息框 -> 一旦找到就关闭
使用 Excel 文件完成主要工作
当一切都完成时停止子线程

当您使用 pywin32 时，它还可用于捕获和关闭消息框。一个 Thread 类来完成这项工作：

# ButtonClicker.py

import time
from threading import Thread, Event
import win32gui, win32con


class ButtonClicker(Thread):

    def __init__(self, title:str, interval:int):
        Thread.__init__(self)
        self._title = title 
        self._interval = interval 
        self._stop_event = Event()   

    def stop(self):
        '''Stop thread.'''
        self._stop_event.set()

    @property
    def stopped(self):
        return self._stop_event.is_set()

    def run(self):
        while not self.stopped:
            try:
                time.sleep(self._interval)
                self._close_msgbox()
            except Exception as e:
                print(e, flush=True)

    def _close_msgbox(self):
        # find the top window by title
        hwnd = win32gui.FindWindow(None, self._title)
        if not hwnd: return

        # find child button
        h_btn = win32gui.FindWindowEx(hwnd, None,'Button', None)
        if not h_btn: return

        # show text
        text = win32gui.GetWindowText(h_btn)
        print(text)

        # click button        
        win32gui.PostMessage(h_btn, win32con.WM_LBUTTONDOWN, None, None)
        time.sleep(0.2)
        win32gui.PostMessage(h_btn, win32con.WM_LBUTTONUP, None, None)
        time.sleep(0.2)

最后，您的代码可能如下所示：

from ButtonClicker import ButtonClicker


# 1. start a child thread
# ButtonClicker instance tries to catch window with specified `title` at a user defined frequency. 
# In your case, the default title for Excel message box is `Microsoft Excel`.
listener = ButtonClicker("Microsoft Excel", 3)
listener.start()


# 2. do your work with Excel file as before
# though it might be blocked by message box, the concurrent child thread will close it

ms_excel_app = win32.gencache.EnsureDispatch('Excel.Application')
ms_excel_app.Visible = True
ms_excel_app.DisplayAlerts = False

template_file = r"C:\Templates_for_test\macro_test.xlsm"
...

# 3. close the child thread finally
listener.stop()

在Microsoft Excel中处理VBA弹出消息框

1 个答案: