Question

我有一个如下的javascript对象。我必须在AddressTotal下对数据进行排序，仅按以下顺序检查。 1.如果任何元素具有“ Prime”：true，则首先将其放在AddressTotal下。 2.如果没有“ Prime”：true，则对“ Createdate”降序排序。

请注意，关于“ Createdate”格式，可以解决。

var x = {
    "accts": [{
            "Id": "Acc1",
            "Person": true,
            "Name": "Hello Roy",
            "ExternalID": "123456",
            "AddressTotal": [{
                    "Account": "Acc1",
                    "Id": "Ad3",
                    "Name": "1 camac Street",
                    "City": "Chennai",
                    "State": "KN",
                    "Zip": "23451",
                    "AddType": "office",
                    "Prime": false,
                    "RecTypeId": "R3",
                    "Createdate": "5th Feb 2018"
                }, {
                    "Account_vod__c": "Acc2",
                    "Id": "Ad2",
                    "Name": "1 strand Road",
                    "City": "Mumbai",
                    "State": "JK",
                    "Zip": "12345",
                    "AddType": "College",
                    "Prime": false,
                    "RecTypeId": "R2",
                    "Createdate": "2nd Feb 2018"
                }, {
                    "Account": "Acc1",
                    "Id": "Ad1",
                    "Name": "1 Park Street",
                    "City": "Bangalore",
                    "State": "TN",
                    "Zip": "74324",
                    "AddType": "School",
                    "Prime": true,
                    "RecTypeId": "R1",
                    "Createdate": "1st Feb 2018"
                }
            ],
            "Rectype": {
                "Name": "ABC",
                "Id": "Id1"
            }
        }
    ],
    "hasAccess": ["A1"]
}

有人可以建议我出路吗？

Answer 1

这是一个非常标准的sorting problem。

首先测试两个元素的素数，然后比较创建日期的Date值。

您不能直接比较Createdate，因为这将导致两个字符串的字母比较，而不是时间戳的数学比较。

var x = {
  "accts": [{
    "Id": "Acc1",
    "Person": true,
    "Name": "Hello Roy",
    "ExternalID": "123456",
    "AddressTotal": [{
      "Account": "Acc1",
      "Id": "Ad3",
      "Name": "1 camac Street",
      "City": "Chennai",
      "State": "KN",
      "Zip": "23451",
      "AddType": "office",
      "Prime": false,
      "RecTypeId": "R3",
      "Createdate": "5th Feb 2018"
    }, {
      "Account_vod__c": "Acc2",
      "Id": "Ad2",
      "Name": "1 strand Road",
      "City": "Mumbai",
      "State": "JK",
      "Zip": "12345",
      "AddType": "College",
      "Prime": false,
      "RecTypeId": "R2",
      "Createdate": "2nd Feb 2018"
    }, {
      "Account": "Acc1",
      "Id": "Ad1",
      "Name": "1 Park Street",
      "City": "Bangalore",
      "State": "TN",
      "Zip": "74324",
      "AddType": "School",
      "Prime": true,
      "RecTypeId": "R1",
      "Createdate": "1st Feb 2018"
    }],
    "Rectype": {
      "Name": "ABC",
      "Id": "Id1"
    }
  }],
  "hasAccess": ["A1"]
};
//TEST
var arr = x.accts[0].AddressTotal.sort(function sorter(a, b) {
  if (a.Prime) {
    return -1;
  }
  if (b.Prime) {
    return 1;
  }
  return new Date(a.Createdate).getTime() - new Date(b.Createdate).getTime();
});
console.log(arr);

顺便说一句，accts是不是一个对象而不仅仅是一个数组的原因吗？

排序部分javascript对象

1 个答案: