我正在尝试通过UDP创建消息传递应用程序,并使其能够同时连续发送和接收。我不知道该如何实现,并且尝试了一些方法。以下是我到目前为止的代码,有人可以指出我做错了什么或需要添加什么?谢谢。
open System
open System.Net
open System.Net.Sockets
open System.Text
printfn "Receive port: "
let receivePort = Console.ReadLine() |> int
let receivingClient = new UdpClient(receivePort)
let ReceivingIpEndPoint = new IPEndPoint(IPAddress.Any, 0)
printfn "Send address: "
let sendAddress = IPAddress.Parse(Console.ReadLine())
printfn "Send port: "
let sendPort = Console.ReadLine() |> int
let sendingClient = new UdpClient()
let sendingIpEndPoint = new IPEndPoint(sendAddress, sendPort)
let rec loop() =
let receive = async {
try
let! receiveResult = receivingClient.ReceiveAsync() |> Async.AwaitTask
let receiveBytes = receiveResult.Buffer
let returnData = Encoding.ASCII.GetString(receiveBytes)
printfn "%s" returnData
with
| error -> printfn "%s" error.Message
}
receive |> ignore
printfn "Send message: "
let (sendBytes: byte array) = Encoding.ASCII.GetBytes(Console.ReadLine())
try
sendingClient.Send(sendBytes, sendBytes.Length, sendingIpEndPoint) |> ignore
with
| error -> printfn "%s" error.Message
loop()
loop()
Console.Read() |> ignore
答案 0 :(得分:2)
代码中一个明显的问题是,您创建了一个异步计算receive
,然后忽略了它,而没有启动它。这意味着您当前的版本仅在发送。
我假设您打算在后台启动接收过程。为此,我们首先将receive
和send
定义为两个单独的异步函数:
let receive () = async {
try
let! receiveResult = receivingClient.ReceiveAsync() |> Async.AwaitTask
let receiveBytes = receiveResult.Buffer
let returnData = Encoding.ASCII.GetString(receiveBytes)
printfn "%s" returnData
with
| error -> printfn "%s" error.Message }
let send () = async {
printfn "Send message: "
let (sendBytes: byte array) = Encoding.ASCII.GetBytes(Console.ReadLine())
try
sendingClient.Send(sendBytes, sendBytes.Length, sendingIpEndPoint) |> ignore
with
| error -> printfn "%s" error.Message }
现在,有多种不同的“同时”发送和接收方式,具体取决于您“同时”的含义。您可以在后台开始接收,然后同时发送,然后等待直到发送和接收都完成后再循环:
let rec loop() = async {
let! wait = Async.StartChild (receive ())
do! send ()
do! wait
return! loop() }
loop() |> Async.Start
或者,您也可以启动两个循环,一个循环保持发送,另一个循环保持尽可能快的接收速度:
let rec loop1() = async {
do! receive ()
return! loop1() }
let rec loop2() = async {
do! send ()
return! loop2() }
loop1() |> Async.Start
loop2() |> Async.Start