MySQL SUM函数不适用于Categori ID的多行顺序

Question

我想从Survey_result表中列出差，公平，好，很好，很好，是，否的总投票，但查询仅一个时间循环。

这是Survey_result表。

这是查询结果

SELECT
categori.s_categori_id,
categori.categori_name_en,
categori.categori_name_ar,
categori.categori_type,
question.survey_id,
question.question_en,
question.question_ar,
SUM(result.poor) AS poor,
SUM(result.fair ) AS fair,
SUM(result.good) AS good,
SUM(result.vgood) AS vgood,
SUM(result.excellent) AS excellent,
SUM(result.yes) AS yes,
SUM(result.no) As no,
result.comment 
FROM
survey_categori AS categori
INNER JOIN survey_questions AS question ON categori.s_categori_id = 
question.s_categori_id
INNER JOIN survey_result AS result ON result.s_question_id = 
question.survey_id
WHERE
categori.survey_type = 'class'
GROUP BY
question.survey_id

Answer 1

您必须在我在查询中添加的字段下方添加分组依据

categori.s_categori_id,
categori.categori_name_en,
categori.categori_name_ar,
categori.categori_type,
question.survey_id,
question.question_en,
question.question_ar,
SUM(result.poor) AS poor,
SUM(result.fair ) AS fair,
SUM(result.good) AS good,
SUM(result.vgood) AS vgood,
SUM(result.excellent) AS excellent,
SUM(result.yes) AS yes,
SUM(result.no) As no,
result.comment 
FROM
survey_categori AS categori
INNER JOIN survey_questions AS question ON categori.s_categori_id = 
question.s_categori_id
INNER JOIN survey_result AS result ON result.s_question_id = 
question.survey_id
WHERE
categori.survey_type = 'class'
GROUP BY
question.survey_id,categori.categori_name_en,
categori.categori_name_ar,
categori.categori_type,
question.question_en,
question.question_ar

Answer 2

  

我想从我的Survey_result表中列出差，公平，好，很好，很好，是，否的总投票

这听起来像您想要整个调查的总数。如果是这样，则不应使用GROUP BY。要获得一行：

SELECT SUM(result.poor) AS poor,
       SUM(sr.fair ) AS fair,
       SUM(sr.good) AS good,
       SUM(sr.vgood) AS vgood,
       SUM(sr.excellent) AS excellent,
       SUM(sr.yes) AS yes,
       SUM(sr.no) As no
FROM survey_categori sc INNER JOIN
     survey_questions sq
     ON sc.s_categori_id = sq.s_categori_id INNER JOIN
     survey_result sr
     ON sr.s_question_id = sq.survey_id
WHERE c.survey_type = 'class';

如果您想要结果集中有多行，则可以使用GROUP BY。然后，GROUP BY中的每一列（或表达式）将（通常）添加到SELECT中。例如，如果您希望每个调查一行，那么您将：

SELECT sq.survey_id,
       SUM(. . .)
       . . .
FROM . . .
GROUP BY sq.survey_id