如果我调用pojo类的get方法,它将给出一个错误。这是我的pojo课

时间:2018-08-12 11:05:48

标签: android

  

我正在尝试使用POJO类对象将数据从一个活动发送到另一个活动。   但是如果我调用get()方法,该应用程序将无法运行   没有get方法的应用程序运行       包com.example.user.bankemployee;

import java.io.Serializable;
import java.util.ArrayList;
import java.util.List;

public class Employee implements Serializable{
    private String employeeName;
    private String employeeId;
    private String age;
    private String gender;
    private String phone;
    private String email;
    private String city;
    private List<String>skill=new ArrayList<>();

    public Employee() {
    }

    public Employee(String employeeName, String employeeId, String age) {
        this.employeeName = employeeName;
        this.employeeId = employeeId;
        this.age = age;
    }

    public String getEmployeeName() {
        return employeeName;
    }

    public String getEmployeeId() {
        return employeeId;
    }

    public String getAge() {
        return age;
    }

    public List<String> getSkill() {
        return skill;
    }

    public void setSkill(List<String> skill) {
        this.skill = skill;
    }

    public String getGender() {
        return gender;
    }
    public void Next(View view) {
  

这是意图代码

    Employee employee=new Employee(empName,empId,age);

    Intent intent=new Intent(this,Step2.class);
    intent.putExtra("step1",employee);

    startActivity(intent);
}
  

这是主要活动

public class EmployeeList extends AppCompatActivity {
String empName,empId,age,Gender,phone,email,city;
List<String> skill=new ArrayList<>();
TextView tb;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_employee_list);
    tb=findViewById(R.id.TB);
    Employee employee=(Employee) getIntent().getSerializableExtra("step1");
    empName=employee.getEmployeeName();
    empId=employee.getEmployeeId();
    age=employee.getAge();
  

如果我这样做,它不会显示任何错误,否则应用会继续停止

public class EmployeeList extends AppCompatActivity {
    String empName,empId,age,Gender,phone,email,city;
    List<String> skill=new ArrayList<>();
    TextView tb;
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_employee_list);
        tb=findViewById(R.id.TB);
        Employee employee=(Employee) 
         getIntent().getSerializableExtra("step1");
        //empName=employee.getEmployeeName();
        //empId=employee.getEmployeeId();
        //age=employee.getAge();

1 个答案:

答案 0 :(得分:0)

与其将“雇员”对象直接放置在意图上,请尝试创建捆绑并将雇员添加到该捆绑中。然后,将捆绑包额外添加到Intent中。 开始活动时,请恢复捆绑包并找到员工。尝试这种方式。

另外,正如Mike M.所说,请确保您在适当的活动中恢复了意图。