宁静的Web服务-@Produces（MediaType.APPLICATION_XML）中的错误

Question

我试图创建一个简单的Restful Web Service，但是当我尝试调试它时，“回头客”如图所示发生了错误。我可以知道是什么原因吗？返回包含数据的客户Customer时，似乎无法使用JAXB将Java对象转换为XML。

package com.mkyong.rest;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;

@Path("/xml/customer")
public class XMLService {

@GET
@Path("/{pin}")
@Produces(MediaType.APPLICATION_XML)
public Customer getCustomerInXML(@PathParam("pin") int pin) {

    Customer customer = new Customer();
    customer.setName("mkyong");
    customer.setPin(pin);

    return customer;

}

}

package com.mkyong.rest;
import javax.xml.bind.annotation.*;
import javax.xml.bind.annotation.XmlAttribute;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;

@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "", propOrder = {
    "name",
    "pin"
})
@XmlRootElement(name = "customer")
public class Customer {

    String name;
    int pin;

    @XmlElement
    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    @XmlAttribute
    public int getPin() {
        return pin;
    }

    public void setPin(int pin) {
        this.pin = pin;
    }

}

http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd“>     宁静的Web应用程序

<servlet>
    <servlet-name>JAVA API</servlet-name>
    <servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
    <init-param>
        <param-name>jersey.config.server.provider.packages</param-name>
        <param-value>com.mkyong.rest</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
    <servlet-name>JAVA API</servlet-name>
    <url-pattern>/rest/*</url-pattern>
</servlet-mapping>

Answer 1

我在此示例中发现了错误，最新的Eclipse IDE已弃用xml jar，您必须在运行和调试时（在配置中）在IDE中手动将其重新添加–