Question

我正在使用Spring JPA规范根据表行ID过滤搜索结果。但是结果不会按搜索条件过滤。我认为执行流程是错误的。

实体人：

public class Person{

.....

@OneToMany
List<Role> roles;

}

Entity Role:
public class Role{

....

UUID id;

@ManyToOne(fetch = FetchType.EAGER)

Person person;

}

规范服务类别：

@Override

public Page<Person> PersonSearch(final Pageable pageable) {
UUID id ="456d5716-fb6b-4a4d-91b4-4ffddb1743b8";
Person prsn = new Person();
Specification<Person> specification = Builder
            .build(prsn);
specification = Builder.addIds(id,specification);
final Page<Person> page = repository.findAll(specification, pageable);
final List<Person> list = new ArrayList<>();
page.forEach(item -> list.add(list.add(item));
return new PageImpl<>(list, pageable, page.getTotalElements());

}

Builder类别：

public static Specification<Person> build(final Person prsn) {
    final List<Specification<Person>> specs = new ArrayList<>();
    hasId(prsn,specs);
    Specification<Person> result = specs.get(0);
    for (int i = 1; i < specs.size(); i++) {
        result = Specifications.where(result).and(specs.get(i));
    }
    return result;
}

public static Specification<Person> hasId(final Person prsn final List<Specification<Person>> specs) {
    if (StringUtils.isNotEmpty(example.getId())) {
        specs.add(PersonSpecifications.hasId(example.Id()));
    }
}   

public static Specification<Person>  addIds(final UUID id, final Specification<Person> specs) {
    Specification<Person> result = specs;
    if (ud != null) {
        result = Specifications.where(result).and(PersonSpecifications.addIds(id));
    }
    return result;
}

规范类别：

public static Specification<Person> hasId(final UUID id) {
return (root, query, cb) -> cb.equal(root.get("uuid"), id);
    };
}

public static Specification<Person> addIds(final UUID id) {
return (root, query, cb) -> {
    query.distinct(true);
    Join<Person, Role> role = root.join("roles",
            JoinType.INNER);
    return cb.equal(role.get("uuid"), id);
    };
}

表格行：

“ 406d5716-fb6b-4a4d-91b4-4ffddb1743b8”，“ e5c777d9-554a-43f2-be4e-26cb5f561a84”;

“ 456d5716-fb6b-4a4d-91b4-4ffddb1743b8”，“ e5c777d9-554a-43f2-be4e-26cb5f561a84”;

根据搜索条件执行repository.findAll（规范，可分页）后，我应该在搜索结果中仅得到一行（“ 456d5716-fb6b-4a4d-91b4-4ffddb1743b8”，“ e5c777d9-554a-43f2-be4e” -26cb5f561a84“），但我同时获得了两行。

有人可以帮助我吗？预先感谢。

JPA春季加入无法正常工作

0 个答案: