Question

如何在Laravel的验证规则中使用两个属性。这是我的函数，其中有2个变量groupid和grouppassword。目前仅使用groupid。

public function groupPasswordValidationReal(Request $request){
    $groupid = $request->input('groupid');
    $grouppassword = $request->input('grouppassword');

    $validator = \Validator::make($request->all(), [
        'groupid' => [new ValidRequest] //How to pass grouppassword in this function???
    ]);

    return redirect('home')->with('success', 'Request is send!');
}

如何将两者都传递给我的验证类？在这里，您可以看到验证类中的功能。

namespace App\Rules;

use Illuminate\Contracts\Validation\Rule;
use App\Group;

class ValidTest implements Rule
{
    public function passes($attribute, $value)
    {
        //$value is groupid
        $validPassword = Group::where([['idgroups', $value],['group_password', /*Here I need grouppassword*/]])->first();
        if($validPassword){
            return true;
        }else{
            return false;
        }
    }

    public function message()
    {
        return 'Wrong Password!';
    }
}

Answer 1

将属性和构造函数添加到您的 ValidTest类。将所需的值作为参数传递给新对象。

ValidTest.php

namespace App\Rules;

use Illuminate\Contracts\Validation\Rule;
use App\Group;

class ValidTest implements Rule
{
    /**
     * The group password.
     *
     * @var string
     */
    public $groupPassword;

    /**
     * Create a new rule instance.
     *
     * @param  \App\Source  $source
     * @param  string  $branch
     * @return void
     */
    public function __construct($groupPassword)
    {
        $this->groupPassword = $groupPassword;
    }
    public function passes($attribute, $value)
    {
        //$value is groupid
        //$this->groupPassword is group_password
        $validPassword = Group::where([['idgroups', $value],['group_password', $this->groupPassword]])->first();
        if($validPassword){
            return true;
        }else{
            return false;
        }
    }

    public function message()
    {
        return 'Wrong Password!';
    }
}

控制器

public function groupPasswordValidationReal(Request $request){
    $groupid = $request->input('groupid');
    $grouppassword = $request->input('grouppassword');

    $validator = \Validator::make($request->all(), [
        'groupid' => new ValidTest($grouppassword)
    ]);

    return redirect('home')->with('success', 'Request is send!');
}

来源：custom-validation-rules-in-laravel-5-5

注意：这不是经过测试的解决方案。

Answer 2

我认为您可以在此处使用闭包。像这样：

$validator = \Validator::make($request->all(), function() use ($groupid, $grouppassword) {
        $validPassword = Group::where([['idgroups', $value],['group_password', $grouppassword]])->first();
        if($validPassword){
            return true;
        }else{
            return false;
        }
}

我还没有运行它。

Answer 3

像使用Rule constructor

class ValidUser implements Rule
{
    private $grouppassword;

    /**
     * Create a new rule instance.
     *
     * @return void
     */
    public function __construct($grouppassword)
    {
        $this->grouppassword = $grouppassword;
    }

    /**
     * Determine if the validation rule passes.
     *
     * @param  string  $attribute
     * @param  mixed  $value
     * @return bool
     */
    public function passes($attribute, $value)
    {
        // $this->grouppassword
        // $groupid = $value
        // Do your logic...
        return true;
    }

    /**
     * Get the validation error message.
     *
     * @return string
     */
    public function message()
    {
        return 'The :attribute must something...';
    }
}

用法

Route::post('/user', function (Request $request) {
    // Parameter validation
    $validator = Validator::make($request->all(), [
        'groupid' => 'required',
        'grouppassword' => ['required', new ValidUser($request->groupid), ]
    ]);

    if ($validator->fails())
        return response()->json(['error' => $validator->errors()], 422);
});

Answer 4

如果您从Request类调用验证，则可以访问额外的值，例如

request()->validate([
    'groupid' => [new ValidTest(request()->input('grouppassword'))]
]);

如何在验证规则类Laravel中使用2个属性

4 个答案: