我有三个表:客户,订单和订单项。它们设置如下:
CREATE TABLE cust_account(
cust_id DECIMAL(10) NOT NULL,
first VARCHAR(30),
last VARCHAR(30),
address VARCHAR(50),
PRIMARY KEY (cust_id));
CREATE TABLE orders(
order_num DECIMAL(10) NOT NULL,
cust_id DECIMAL(10) NOT NULL,
order_date DATE,
PRIMARY KEY (order_num));
CREATE TABLE line_it(
order_id DECIMAL(10) NOT NULL,
line_id DECIMAL(10) NOT NULL,
item_num DECIMAL(10) NOT NULL,
PRIMARY KEY (order_id, line_id),
FOREIGN KEY (item_id) REFERENCES products);
我需要编写一个查询,选择要购买3个或更多人购买的商品的客户,他们的姓名和地址。我有以下查询:
SELECT cust_account.cust_id, cust_account.first, cust_account.last, cust_account.address
FROM cust_account
INNER JOIN orders ON cust_account.cust_id = orders.cust_id
INNER JOIN line_it ON orders.order_id = line_it.order_id
GROUP BY cust_account.cust_id, cust_account.last
HAVING COUNT(line_it.item_num) = (
SELECT COUNT (DISTINCT order_num > 3)
FROM line_it
);
我什至需要使其成为子查询吗?我有点迷路。感谢任何帮助,谢谢。
答案 0 :(得分:1)
从“三个或更多人购买的物品”开始。您可以通过以下方式获得这些信息:
select li.item_id
from line_item li join
order_info oi
on li.order_id = oi.order_id
group by li.item_id
having count(distinct oi.customer_id) >= 3;
现在,您需要该组中的客户。嗯:
select distinct ca.*
from customer_account ca join
orderinfo oi
on ca.customer_id = oi.customer_id join
line_item li
on li.order_id = oi.order_id
where li.item_id in (select li.item_id
from line_item li join
order_info oi
on li.order_id = oi.order_id
group by li.item_id
having count(distinct oi.customer_id) >= 3
);
您也可以使用窗口功能表达这一点:
select distinct ca.*
from (select ca.*, count(distinct customer_id) over (partition by li.item_id) as num_customers_on_item
from customer_account ca join
orderinfo oi
on ca.customer_id = oi.customer_id join
line_item li
on li.order_id = oi.order_id
) ca
where num_customers_on_item >= 3;
答案 1 :(得分:0)
您可以使用以下查询
SELECT distinct customer_account.* FROM line_item, order_info ,customer_account where item_id in (
--Selecting only item purchased 3 or more
SELECT item_id FROM line_item group by item_id having count(1) >=3
)
and line_item.order_id = order_info.order_id
and customer_account.customer_id = order_info.customer_id
;