通过不同的ID根据数据库值动态检查“爱好”复选框

时间:2018-08-10 14:10:32

标签: javascript php jquery mysql ajax

我的问题:第一次我单击编辑按钮,然后根据数据库表值选中了复选框,然后第二次我单击其他编辑按钮,然后未取消选中第一次复选框值,我不知道我的代码有什么错误。 请检查我的代码。

示例:在Form屏幕截图中,当我单击第一个编辑按钮时,然后选中了复选框值(如cricket,hokky,chess);在第二个编辑按钮后,我单击了复选框值(cricket),但问题是第一次复选框的值(例如板球,嬉皮,象棋)未被选中,请帮助我,

请检查以下屏幕截图:

Form Screenshot

HTML代码:

    <form id="crudform" method="post">
        <label>Hobby:</label>
        <input type="checkbox" name="hobby[]" value="cricket">Cricket
        <input type="checkbox" name="hobby[]" value="hokky">Hobby
        <input type="checkbox" name="hobby[]" value="chess">Chess
        <input type="submit" name="submit" value="Add">
    </form>

<div class="table"></div>

Database Table ScreenShot

PHP代码:

<table>
        <thead>
            <tr>
                <th>Hobby</th>
                <th colspan="2">Action</th>
            </tr>
        </thead>
        <tbody>
            <?php if(mysqli_num_rows($result)>0){ ?>
                <?php while($data = mysqli_fetch_assoc($result)){ ?>
            <tr>
                <td><?php echo $data['hobby'];?></td>
                <td><button name="edit" data-id = <?php echo $data['id'];?> class="btn btn-info">Edit</button></td>
                <td><button class="btn btn-danger">Delete</button></td>
            </tr>
        <?php } ?>
        <?php } ?>
        </tbody>
    </table>

jQuery代码:

<script type="text/javascript">
$("button[name=edit]").click(function(){
    var id = $(this).attr("data-id");

    var hobbyss = [];
    $(":checkbox").each(function(index,element){
        hobbyss.push($(this).val());
    });


    $.ajax({
        url:"http://localhost/interview/crud_checkbox/edit.php",
        method:"post",
        data:{id:id},
        dataType:"json",
        success:function(response){
            var hobby = response.hobby.split(",");          // ["cricket", "hokky", "chess"]    

            $.each(hobby,function(index,element){
                if($.inArray(element,hobbyss) >= 0){
                    console.log($("input[value="+element+"]").prop("checked",true));
                }
            }); 
        }
    });
});
</script>

1 个答案:

答案 0 :(得分:0)

每次在编辑按钮上单击添加的已选中属性,但您忘记删除先前已选中复选框的已选中属性。因此您需要取消选中“编辑”按钮上的所有复选框,如下所示。

$("button[name=edit]").click(function(){

	$('input[name=hobby\\[\\]]').prop('checked',false);
    
    //rest of your code here 
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="crudform" method="post">
	<label>Hobby:</label>
	<input type="checkbox" name="hobby[]" value="cricket" checked >Cricket
	<input type="checkbox" name="hobby[]" value="hokky">Hobby
	<input type="checkbox" name="hobby[]" value="chess" checked >Chess
	<input type="submit" name="submit" value="Add">
</form>

<button name="edit" data-id ="1" class="btn btn-info">Edit</button>