我想通过单击另一个元素来切换一个元素的类名称。这两个元素都在单独的组件文件中。我不知道如何获取元素的状态并将其传递给另一个元素。请帮助我解决问题。
file1.js
<Button onClick={this.toggleFunction}>Button</Button>
file2.js
<div class="wrapper"></div>
点击按钮后,我想在包装器上切换活动类别。
谢谢
答案 0 :(得分:1)
class MyComponent extends Component {
constructor(props) {
super(props);
this.addActiveClass= this.addActiveClass.bind(this);
this.state = {
active: false,
};
}
toggleClass() {
const currentState = this.state.active;
this.setState({ active: !currentState });
};
render() {
return (
<div
className={this.state.active ? 'your_className': null}
onClick={this.toggleClass}
>
<p>{this.props.text}</p>
</div>
)
}
}
答案 1 :(得分:1)
Parent Component
import React from "react";
import ButtonComponent from "./buttonComponent";
import "./demo.css";
//Parent Component
class Demo extends React.Component {
constructor(props) {
super(props);
this.state = {
active: false
};
}
updateValue = value => {
this.setState({
active: value
});
};
render() {
return (
<div>
<ButtonComponent updateParent={this.updateValue} />
<div
className={
this.state.active ? "dropdownbutton1" : "dropdownbutton1Active"
}
>
<label>First</label>
<br />
<select>
<option value="yes">yes</option>
<option value="no">no</option>
</select>
</div>
</div>
);
}
}
export default Demo;
Child Component
import React from "react";
import ToggleButton from "react-toggle-button";
import "./demo.css";
class ButtonComponent extends React.Component {
constructor(props) {
super(props);
this.state = {
active: false,
defaultValue: 1
};
}
togglebutton = () => {
this.props.updateParent(this.state.active);
this.setState({ active: !this.state.active });
if (this.state.active) {
this.setState({ defaultValue: 1 });
} else {
this.setState({ defaultValue: -1 });
}
};
render() {
return (
<div>
<div className="ToggleButton">
<ToggleButton onClick={this.togglebutton} value={this.state.active} />
</div>
</div>
);
}
}
export default ButtonComponent;