使用preg_match_all我想获取html中的类和数据属性。
下面的示例有效,但,它仅返回类名称或仅 data-id 内容。 / p>
我希望示例模式能够同时找到类和数据ID内容。
我应该使用哪种正则表达式模式?
HTML内容:
<!-- I want to: $matches[1] == test_class | $matches[2] == null -->
<div class="test_class">
<!-- I want to: $matches[1] == test_class | $matches[2] == 1 -->
<div class="test_class" data-id="1">
<!-- I want to: $matches[1] == test_class | $matches[2] == 1 -->
<div id="test_id" class="test_class" data-id="1">
<!-- I want to: $matches[1] == test_class test_class2 | $matches[2] == 1 -->
<div class="test_class test_class2" id="test_id" data-id="1">
<!-- I want to: $matches[1] == 1 | $matches[2] == test_class test_class2 -->
<div data-id="1" class="test_class test_class2" id="test_id" >
<!-- I want to: $matches[1] == 1 | $matches[2] == test_class test_class2 -->
<div id="test_id" data-id="1" class="test_class test_class2">
<!-- I want to: $matches[1] == test_class | $matches[2] == 1 -->
<div class="test_class" id="test_id" data-id="1">
无法正常运行的正则表达式:
$pattern = '/<(div|i)\s.*(class|data-id)="([^"]+)"[^>]*>/i';
preg_match_all($pattern, $content, $matches, PREG_SET_ORDER);
谢谢。
答案 0 :(得分:3)
为什么不使用DOM解析器呢?
您可以使用//div[@class or @data-id]
之类的XPath表达式来定位元素,然后提取其属性值
$doc = new DOMDocument();
$doc->loadHTML($html);
$xpath = new DOMXpath($doc);
$divs = $xpath->query('//div[@class or @data-id]');
foreach ($divs as $div) {
$matches = [$div->getAttribute('class'), $div->getAttribute('data-id')];
print_r($matches);
}
答案 1 :(得分:2)
第二个是Phil的答案,我认为HTML解析器是解决之道。它更安全,可以处理很多复杂的事情。
话虽如此,如果您想在示例中尝试使用正则表达式,则将是这样的:
<(?:div|i)(?:.*?(?:class|data-id)="([^"]+)")?(?:.*?(?:class|data-id)="([^"]+)")?[^>]*>