Question

你们可以在Jupyter note中运行我的代码，请告诉我它有什么问题吗？我似乎不明白为什么它无法正常运行。每当我从库存中选择物品时，它都会给我带来结束的机会。我希望在龙打败时打印代码，并将打印语句打印到下一个房间。

import sys

print("""Hello! Type 1 to Continue""")

#ice sword - a

#fire sword - b

#electric sword - c

inv = {'a':'Ice Sword'}

#function to display the inventory

def display():
    print("type 1 to display your inventory\n")

n = input()

if int(n)==1:

    for i in inv:

        print(i +" - "+ inv[i])

    sequence = ['c','a','b']

for i in range(0,4):

#room-1 Fire dragon - ice sword win-firesword

    if i==0:

        print("You are in room-1 a FIRE DRAGON appears\n")

display()

print("choose your Item")

x = input()

if x == 'a' and i==0:

    print("The fire dragon is defeated proceed to next room\n")
    print("You have acquired a new Item 'Fire Sword'\n")

    inv['b'] = 'Fire Sword'

else:
    print("---GAME OVER---")




#room-2 Electric dragon - ice sword win-electric sword

if i==1:

    print("You are in room-2 a ELECTRIC DRAGON appears\n")

display()

print("choose your Item")

x = input()

if x=='a' and i==1:

    print("The electric dragon is defeated you proceed next room\n")

    print("You have acquired a new Item 'Electric Sword'\n")

    inv['c'] = 'Electric Sword'

else:

    print("---GAME OVER---")



#room-3 Ice dragon - fire sword win-key

if i==2:

    print("You are in room-3 a Ice dragon appears\n")

    display()

print("choose your Item")

x = input()

if x=='b' and i==2:

    print("The Ice dragon is defeated you __ next room\n")

    print("You have acquired a new Item 'Key'\n")

    inv['d'] = 'Key'

else:

    print("---GAME OVER---")



#room-4 Dark beast Ganon specific order ([c a b])

if i==3:

    print("Use the key you won to enter the last room\n")

display()

print("choose your Item")

x = input()

if x=='d' and i==3:

    print("The Final boss DARK BEAST GANON appears\n")

else:

    print("---GAME OVER---")



#used the key and the boss appears

print("to defeat this boss you need to use a specific combination of the swords\n")

print("Enter the sequence one by one and press enter after every value")

a = []

for i in range(0,3):

    x = input()

a.append(x)

if a == sequence:

    print("Congratulation you have completed the game")



#sys.exit()



else:

    print("---GAME OVER---")

Answer 1

这是一个构造错误的问题。我们不仅需要更多有关所发生一切事情的上下文，而且我还建议您特别指出出现问题的代码行，在这种情况下，还应指出“游戏结束”的代码行。

此外，无论是否在Jupyter中运行都无关紧要，只要您使用的Python版本相同，它就可以在任何运行位置以相同的方式工作。

Answer 2

看起来您的错误是此循环的副作用：

for i in range(0,4):
    if i==0:  #room-1 Fire dragon - ice sword win-firesword
        print("You are in room-1 a FIRE DRAGON appears\n")

display()

print("choose your Item")
x = input()
if x == 'a' and i==0:

请注意，即使仅在i==0时打印，循环仍会通过i=1，i=2和i=3执行。我突出显示的最后一行if x == 'a' and i==0:的值为False，因为此时i==0为False-i为3（因为循环已完成）。

基于文本的地牢游戏python

2 个答案: