Question

我将多个查询值带到我的前端，并使用一个数组来实现。当我在if语句之前回显我的$hold['POAmount'];值时，它会按预期返回253{"Sum":10,"POAmount":-10}，尽管不要将其与期望的输出混淆。但是在输入我的if语句后，返回页面的响应为{"Sum":10,"POAmount":-10}。我认为也许在fetch_assoc()上使用fetch_array()会有所作为，但这无济于事。这是我得到的：

<?php
include '../../inc/dbinfo.inc';

ini_set("log_errors", 1);
ini_set("error_log", "/tmp/php-error.log");
error_log( "#################################################     FT-SUM-INVOICES.PHP    #################################################" );

$inv = $_POST['inv'];
$status = $_POST['stat'];

//Get PO # From invoice id
$getPO = "SELECT VendorPOID1, VdrInvoiceAmount FROM tblVendorInvoices WHERE VENDORINVOICEID =?";
$exgetPO = $conn->prepare($getPO);
$exgetPO->bind_param("i", $inv);
$exgetPO->execute();
$obj = $exgetPO->get_result();
$hold = $obj->fetch_assoc();
$po = $hold['VendorPOID1'];
$currentInAmount = $hold['VdrInvoiceAmount'];

$cn = 3; //paid status

$getPOAmount = "SELECT POAmount FROM tblVendorPOs WHERE VENDORPOID = ?";
$poAmount = $conn->prepare($getPOAmount);
$poAmount->bind_param("i",$po);
$poAmount->execute();
$obj3 = $poAmount->get_result();
$hold = $obj3->fetch_assoc(); //Total PO Amount


if($status == 3){
  echo json_encode($hold['POAmount']);
  //Get Sum of invoices on po + current invoice
  $qr = "SELECT SUM(VdrInvoiceAmount) AS Sum FROM tblVendorInvoices WHERE VENDORPOID1 = ? AND VdrInvoiceStatusID = ?";
  $getSum = $conn->prepare($qr);
  $getSum->bind_param("ii", $po, $cn);
  $getSum->execute();
  $obj2 = $getSum->get_result();
  $hold = $obj2->fetch_assoc();

  $hold['Sum'] += $currentInAmount;

  $hold['POAmount'] -= $hold['Sum'];  //remaining balance

  if($hold['Sum'] == NULL){
    $hold['Sum'] = 0;
  }

  echo json_encode($hold);
}else{
 //Get Sum of invoices on po
 $qr = "SELECT SUM(VdrInvoiceAmount) AS Sum FROM tblVendorInvoices WHERE VENDORPOID1 = ? AND VdrInvoiceStatusID = ?";
  $getSum = $conn->prepare($qr);
  $getSum->bind_param("ii", $po, $cn);
  $getSum->execute();
  $obj2 = $getSum->get_result();
  $hold = $obj2->fetch_assoc();
  if($hold['Sum'] == NULL){
    $hold['Sum'] = 0;
  }

  $hold['POAmount'] -= $hold['Sum'];

  echo json_encode($hold);
}

?>

我上面描述的if语句是if($status == 3){，我没有从网页或PHP错误日志中收到任何错误。

我的问题摘要：

当我从中减去总和时，

$hold['POAmount']被认为是null。因此它以-$hold['Sum']的形式出现。开头不应该为null。输入我的if语句后，它变成null。

当前输出：{"Sum":9,"POAmount":-9} 所需的输出：{"Sum":9,"POAmount":243}

Answer 1

这应该有效（尚未测试）。我更改的是，我已将if语句中的SELECT查询结果分配给另一个名为$ hold2的变量，以使$ hold中的$ hold ['POAmount']值不会被覆盖。

然后我将$ hold变量中的数组（在if语句之前保存SELECT查询的结果）与$ hold2中的数组（在if语句中保存SELECT查询的结果）合并），生成包含POAmount和Sum键的数组。

让我知道这是否行不通以及您遇到了什么错误，我们很乐意为您提供帮助。：）

<?php
include '../../inc/dbinfo.inc';

ini_set("log_errors", 1);
ini_set("error_log", "/tmp/php-error.log");
error_log( "#################################################     FT-SUM-INVOICES.PHP    #################################################" );

$inv = $_POST['inv'];
$status = $_POST['stat'];

//Get PO # From invoice id
$getPO = "SELECT VendorPOID1, VdrInvoiceAmount FROM tblVendorInvoices WHERE VENDORINVOICEID =?";
$exgetPO = $conn->prepare($getPO);
$exgetPO->bind_param("i", $inv);
$exgetPO->execute();
$obj = $exgetPO->get_result();
$hold = $obj->fetch_assoc();
$po = $hold['VendorPOID1'];
$currentInAmount = $hold['VdrInvoiceAmount'];

$cn = 3; //paid status

$getPOAmount = "SELECT POAmount FROM tblVendorPOs WHERE VENDORPOID = ?";
$poAmount = $conn->prepare($getPOAmount);
$poAmount->bind_param("i",$po);
$poAmount->execute();
$obj3 = $poAmount->get_result();
$hold = $obj3->fetch_assoc(); //Total PO Amount


if($status == 3){
  echo json_encode($hold['POAmount']);
  //Get Sum of invoices on po + current invoice
  $qr = "SELECT SUM(VdrInvoiceAmount) AS Sum FROM tblVendorInvoices WHERE VENDORPOID1 = ? AND VdrInvoiceStatusID = ?";
  $getSum = $conn->prepare($qr);
  $getSum->bind_param("ii", $po, $cn);
  $getSum->execute();
  $obj2 = $getSum->get_result();
  $hold2 = $obj2->fetch_assoc();

  $hold = array_merge($hold, $hold2);

  $hold['Sum'] += $currentInAmount;

  $hold['POAmount'] -= $hold['Sum'];  //remaining balance

  if($hold['Sum'] == NULL){
    $hold['Sum'] = 0;
  }

  echo json_encode($hold);
}else{
 //Get Sum of invoices on po
 $qr = "SELECT SUM(VdrInvoiceAmount) AS Sum FROM tblVendorInvoices WHERE VENDORPOID1 = ? AND VdrInvoiceStatusID = ?";
  $getSum = $conn->prepare($qr);
  $getSum->bind_param("ii", $po, $cn);
  $getSum->execute();
  $obj2 = $getSum->get_result();
  $hold2 = $obj2->fetch_assoc();

  $hold = array_merge($hold, $hold2);

  if($hold['Sum'] == NULL){
    $hold['Sum'] = 0;
  }

  $hold['POAmount'] -= $hold['Sum'];

  echo json_encode($hold);
}

?>

输入if语句时，为什么我的数组值不显示？

1 个答案: