Question

是否有办法知道某些代码是否在try catch块下？（特别是在节点中）

我想做的是这样的（使用变量bungleInTry来模拟我要寻找的东西）

let acumulateErrors=[];
let bungleInTry=0;      // This to be removed, it's to simulate the expected behavior

function assert(cond,msg){
  if (!cond){  
    if (underTryCatch())
        throw(Error(msg));   // Somewhere somebody is in control
    else
        acumulateErrors.push(msg);  // I don't want a crash but I have to keep this
  }
}
    
assert(1==2, "1 doesn't equals 2"); 

bungleInTry++;  // (simulating what I am asking)
try{
  assert(3==4, "3 doesn't equals 4");

}catch(error){
  console.log(error.message);
}
bungleInTry--;  // to be removed


console.log(acumulateErrors);

function underTryCatch(){
  return bungleInTry;
}

Answer 1

否，无法检测到将捕获引发的错误，而该信息仅对您的代码不可用。（并且可以说，所有错误都会被捕获，即使它们是由Node自己的错误处理程序捕获的，该错误处理程序会将其转储到控制台并终止进程... :-)）

如何判断代码是否在try catch块下

1 个答案: