我的视图中有html表,我想使用多个过滤器进行过滤。在这种情况下,我有3个过滤器,但我可以有更多过滤器。
这里很少有代码来显示问题
$(document).ready(function () {
$('#datefilterfrom').on("change", filterRows);
$('#datefilterto').on("change", filterRows);
$('#projectfilter').on("change", filterProject);
$('#servicefilter').on("change", filterService);
});
function filterRows() {
var from = $('#datefilterfrom').val();
var to = $('#datefilterto').val();
if (!from && !to) { // no value for from and to
return;
}
from = from || '1970-01-01'; // default from to a old date if it is not set
to = to || '2999-12-31';
var dateFrom = moment(from);
var dateTo = moment(to);
$('#testTable tr').each(function (i, tr) {
var val = $(tr).find("td:nth-child(2)").text();
var dateVal = moment(val, "DD/MM/YYYY");
var visible = (dateVal.isBetween(dateFrom, dateTo, null, [])) ? "" : "none"; // [] for inclusive
$(tr).css('display', visible);
});
}
function filterProject() {
let dumb = this.options.selectedIndex;
dumb = this.options[dumb].innerHTML;
var filter, table, tr, td, i;
filter = dumb.toUpperCase();
table = document.getElementById("testTable");
tr = table.getElementsByTagName("tr");
for (i = 0; i < tr.length; i++) {
td = tr[i].getElementsByTagName("td")[2];
if (td) {
if (td.innerHTML.toUpperCase().indexOf(filter) > -1) {
tr[i].style.display = "table-row";
} else {
tr[i].style.display = "none";
}
}
}
}
function filterService() {
let dumb = this.options.selectedIndex;
dumb = this.options[dumb].innerHTML;
var filter, table, tr, td, i;
filter = dumb.toUpperCase();
table = document.getElementById("testTable");
tr = table.getElementsByTagName("tr");
for (i = 0; i < tr.length; i++) {
td = tr[i].getElementsByTagName("td")[3];
if (td) {
if (td.innerHTML.toUpperCase().indexOf(filter) > -1) {
tr[i].style.display = "table-row";
} else {
tr[i].style.display = "none";
}
}
}
}
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css" integrity="sha384-BVYiiSIFeK1dGmJRAkycuHAHRg32OmUcww7on3RYdg4Va+PmSTsz/K68vbdEjh4u" crossorigin="anonymous">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://rawgit.com/moment/moment/2.2.1/min/moment.min.js"></script>
<div class="row">
<div class="col-md-3">
<h4>Date from</h4>
<input type="date" class="form-control" id="datefilterfrom" data-date-split-input="true">
</div>
<div class="col-md-3">
<h4>Date to</h4>
<input type="date" class="form-control" id="datefilterto" data-date-split-input="true">
</div>
<div class="col-md-2">
<h4>Project</h4>
<select id="projectfilter" name="projectfilter" class="form-control"><option value="1">Test project</option><option value="2">Test2</option></select>
</div>
<div class="col-md-2">
<h4>Service</h4>
<select id="servicefilter" name="servicefilter" class="form-control"><option value="1">Test service</option><option value="2">Test2 service</option></select>
</div>
</div>
<table id="testTable" class="table">
<thead>
<tr>
<th scope="col">#</th>
<th scope="col">Date</th>
<th scope="col">Project</th>
<th scope="col">Service</th>
</tr>
</thead>
<tbody id="report">
<tr>
<td class="proposalId">9</td><td> 17/07/2018</td> <td> Test project</td><td> Test service</td>
</tr>
<tr><td class="proposalId">8</td><td> 18/07/2018</td><td> Test project</td><td> Test2 service</td></tr>
<tr><td class="proposalId">7</td><td> 17/07/2018</td><td> Test2</td><td> Test2 service</td></tr>
<tr style=""><td class="proposalId">3</td><td> 19/07/2018</td><td> Test2</td><td> Test service</td></tr>
</tbody>
</table>
您将拥有这个
这是不对的。因为我只需要测试2个项目,所以一行。
我的问题在哪里以及如何解决?
这里是代码的密码笔
答案 0 :(得分:0)
现在,每个过滤器都有一个单独的功能,每个功能都会忽略其他过滤器的设置并覆盖其结果。
相反,您需要将它们组合成一个函数,该函数将 all 个过滤器考虑在内。
与其将所有代码从字面上组合成一个复杂的函数(这很难维护),一种方法是让单个主函数使所有行可见,然后依次调用其他每个过滤器函数;这些功能只会隐藏正在过滤的行。最后剩下的就是与所有过滤器选择匹配的行。
$(document).ready(function () {
$('#datefilterfrom, #datefilterto, #projectfilter, #servicefilter').on("change", filterAll);
});
function filterAll() {
$('#testTable tr').show();
filterRows();
filterProject();
filterService();
// ...etc
}
function filterRows() { // repeat for filterProject(), filterService(), etc
// same as your original code, except only hide non-matching rows, do not
// show matching rows (because filterAll() already took care of that, and
// you don't want to undo what other filters may have hidden.)
}
(或者,不显示所有内容,而是让每个单独的过滤器逐渐隐藏行,您可以让filterAll()构建一个包含所有行的数组,将其传递给单独的过滤器函数,该函数将从中删除项目,然后使用最终显示/隐藏相应行的最终结果。)
答案 1 :(得分:0)
不会为您全部重写,但会为您提供纯文本搜索的基本概述:
从顶部输入创建过滤器数据数组。通过向每个过滤器控件添加data-col
,您可以轻松确定表中要匹配的列
所以filter数组看起来像这样:
[
{col:3, value:'test project'}
]
然后在行上使用jQuery filter()
,在filterValues数组上使用Array#every()
,并使用每个过滤器对象的列索引查找匹配的单元格文本
var $rows = $('tbody#report tr')
// add a class `table-filter` to all the top filtering elements
var $filters = $('.table-filter').change(function() {
// create array of filter objects
var filterArr = $filters.filter(function() {
return this.value
}).map(function() {
var $el = $(this);
var value = $el.is('select') ? $el.find(':selected').text() : $el.val()
return {
col: $el.data('col'),
value: value.toLowerCase()
}
}).get();
if (!filterArr.length) {
// no filters show all rows
$rows.show()
} else {
// hide all then filter out the matching rows
$rows.hide().filter(function() {
var $row = $(this);
// match every filter to whole row
return filterArr.every(function(filterObj, i) {
var cellText = $row.find('td').eq(filterObj.col).text().trim().toLowerCase();
return cellText.includes(filterObj.value);
})
})
// show the matches
.show()
}
});