Question

我有以下临时表作为查询的输出：

FacilityID      UserID   User_Name
1046            105      John Smith
1046            106      John Smith
1046            110      Jack Welsh 
1091            107      Ana Romero
1091            248      Rebecca Cruz 
1095            418      Alex Sterling

我只需要显示具有相同名称用户的这些设施，并且只有这些名称才能通过查询过滤器。这是为了找出是否有任何设施的用户具有完全相同的名称（即使这些人是不同的人）。因此，考虑到上表，我只需要显示以下内容：

FacilityID      UserID   User_Name
1046            105      John Smith
1046            106      John Smith

Answer 1

您可以使用exists：

select t.*
from t
where exists (select 1
              from t t2
              where t2.FacilityID = t.FacilityID and t2.user_name = t.user_name and
                    t2.UserId <> t.userId and
             );

如果您有返回结果的查询，那么窗口函数也是一个不错的选择：

with t as (<your query here>)
select t.*
from (select t.*, min(userid) over (partition by FacilityID, user_name) as min_ui,
             max(userid) over (partition by FacilityID, user_name) as max_ui
      from t
     ) t
where min_ui <> max_ui;

Answer 2

我会使用exists：

select t.*
from table t
where exists (select 1 
              from table t1 
              where t1.FacilityID = t.FacilityID and 
                    t1.User_Name = t.User_Name and t.userid <> t1.userid
             );

Answer 3

我会使用EXISTS子句：

（示例使用CTE [TEMP]作为测试）

;WITH TEMP (FacilityID, UserID, User_Name) AS (
    SELECT * FROM (
        VALUES
            ('1046','105','John Smith'), 
            ('1046','106','John Smith'), 
            ('1046','110','Jack Welsh'), 
            ('1091','107','Ana Romero'), 
            ('1091','248','Rebecca Cruz'), 
            ('1095','418','Alex Sterling')
    ) AS A (Column1, Column2, Column3)
)


SELECT TEMP.*
FROM TEMP
WHERE EXISTS (SELECT 1 
    FROM TEMP SubT 
    WHERE SubT.FACILITYID = TEMP.FACILITYID 
        AND SubT.USER_NAME = TEMP.USER_NAME 
        AND TEMP.USERID <> SubT.USERID
    )

Answer 4

我将加入我的解决方案：

select FacilityID, UserID, User_Name from (
    select FacilityID, UserID, User_Name
           count(*) over (partition by User_Name) cnt
    from MY_TABLE 
) a where cnt > 1

sql获取由另一列分组的重复列值

4 个答案: