spark-sql中的更新语句

时间:2018-08-09 15:48:22

标签: scala apache-spark-sql

是否有一种方法可以使用spark-sql(使用scala语言)在sql服务器表上执行更新语句?

我需要执行以下查询:

update  MyLog_table
set     Log_FileQueue = xx,
        Log_TotalLine = xx
where   Log_ID = xxx

我尝试了以下语法:

 val jdbcUrl = s"jdbc:sqlserver://${jdbcHostname}:${jdbcPort};database=${jdbcDatabase}"
    val Log_FileIn = spark.read.jdbc(jdbcUrl, s"(select Log_FileIn from log Where   Log_ID = '${Process1Log_ID}' ) as sq", connectionProperties)
    val newLog_FileIn = Log_FileIn.collectAsList().toString().replace("[", "").replace("]", "")

 spark.sql(s"(select '${newLog_FileIn}' as Log_FileQueue, ${NbLine} as Log_TotalLine where Log_ID = '${newLog_id}')")
  .write
  .mode(SaveMode.Append)
  .jdbc(jdbcUrl, "Log", connectionProperties)

但它会产生以下错误:

org.apache.spark.sql.AnalysisException: cannot resolve '`Log_ID`' given input columns: []; line 1 pos 115;
'Project [test_141001.csv AS Log_FileQueue#290, 5 AS Log_TotalLine#29

我也尝试使用“ where”方法:

spark.sql(s"(select '${newLog_FileIn}' as Log_FileQueue, ${NbLine} as Log_TotalLine where Log_ID = '${newLog_id}')")
  .where(s"Log_ID = '${newLog_id}'")
  .write
  .mode(SaveMode.Append)
  .jdbc(jdbcUrl, "Log", connectionProperties)

但是它也不起作用。我收到以下错误:

org.apache.spark.sql.AnalysisException: cannot resolve '`Log_ID`' given input columns: [Log_FileQueue, Log_TotalLine]; line 1 pos 0;
'Filter ('Log_ID = 157456)
+- AnalysisBarrier
      +- Project [ANNONCE-FNAC-VIGICOLIS-GRX-BIZ-2018hfgr071eyzdtrf2_141001.csv AS Log_FileQueue#290, 5 AS Log_TotalLine#291]

任何帮助将不胜感激

1 个答案:

答案 0 :(得分:2)

不起作用。请尝试executeBatch。