Question

我需要基于标志（loginStatus）发送响应，但是在此之前，将发送默认的200响应。如何截取响应？

private void handlePost(HttpRequest request, HttpResponse response) {
    response.setHeader("Content-Type", "text/html");
    HttpEntity entity = ((HttpEntityEnclosingRequest)request).getEntity();

   **// Handling the request here ......**

    Handler mainHandler = new Handler(context.getMainLooper());

    Runnable runnable = new Runnable() {
        @Override
        public void run() {
            HttpEntity respEntity = new EntityTemplate(new ContentProducer() {
                public void writeTo(final OutputStream outstream) throws IOException {
                    OutputStreamWriter writer = new OutputStreamWriter(outstream, "UTF-8");
                    final InputStream in = getContext().getAssets().open( "home.html" );

                    IOUtils.copy(in, writer);
                    writer.flush();
                }
            });
            response.setHeader("Content-Type", "text/html");
            response.setEntity(respEntity);

          **//the loginStatus value is asynchronous so waiting for 5000**

            if(loginStatus){
         **// set status code 201**
                response.setStatusCode(HttpStatus.SC_CREATED);
            } else {
         **// set status code 501**
                response.setStatusCode(HttpStatus.SC_UNAUTHORIZED);
            }
        }
    };

    mainHandler.postDelayed(runnable, 5000);
}

Answer 1

您应该使用一个库来执行此操作，这比自己编写网络层要好。您可以使用OkHttp管理Http Request并实现拦截器，请参见此https://github.com/square/okhttp/wiki/Interceptors
您可以编写实现Interceptor接口的CustomClass并覆盖此方法

@Override
public Response intercept(Chain chain) throws IOException {
    Request request = chain.request();
    Response response = chain.proceed(request);
    if (response.code() = 200) {
        //Do what you want
    }
    Log.d(TAG, "INTERCEPTED:$ " response.toString());
    return response;
}

如何截获从HttpResponse发送的默认200响应？

1 个答案: