Question

我想提取字典的键，但问题是该键用单引号引起来。

from pyspark import SparkContext, SparkConf
import collections,shutil,os

conf = SparkConf().setMaster("local").setAppName("Word_count")
sc=SparkContext(conf=conf)

rdd=sc.textFile("/home/karan/dummy files/patient.csv")
rdd2=sc.textFile("/home/karan/dummy files/doctors.csv")
def nameOfDoc():
    names={}
    with open("/home/karan/dummy files/doctors.csv") as l:
        for x in l:
            nameExt=x.split('\t')
            names[int(nameExt[0])]=nameExt[1]
    return names
docName=sc.broadcast(nameOfDoc())

docId=rdd.map(lambda x:x.split(",")).\
        map(lambda x:(x[3],1)).\
        reduceByKey(lambda x,y:x+y).\
        map(lambda x:(x[1],x[0])).\
        sortByKey(ascending=False).\
        map(lambda x:(x[1],x[0]))
rs=docId.collect()
if os.path.exists("/home/karan/output2"):
    shutil.rmtree("/home/karan/output2")
for x in rs:
    print(docName.value[x[0]],end=" -> ")
    print(x[1])
sc.parallelize(rs).saveAsTextFile("output2")

我的代码给我这个错误

文件“ /home/karan/hospitalsDemo.py”，第28行，在 print（docName.value [x [0]]，end =“->”）KeyError：'2'

Answer 1

for x in rs:
    print(docName.value[x[0]],end=" -> ")
    print(x[1])

我认为Green Cloak Guy将字符串转换为整数是正确的。由于您将x用于x [0]和x [1]，并且还避免了键可能无法转换为整数的情况，因此我认为您应该“

for x in rs:
    try:
        xkey = int(x)
    except:
        xkey = x

    print(docName.value[xkey[0]],end=" -> ")
    print(xkey[1])

如何从python列表中提取单引号

1 个答案: