Question

例如现在是八月，我想要一个选择查询，其结果如下：

+-----------+
| September |
+-----------+
| October   |
+-----------+
| November  |
+-----------+
| December  |
+-----------+
| January   |
+-----------+
| February  |
+-----------+
| March     |
+-----------+
| April     |
+-----------+
| May       |
+-----------+
| June      |
+-----------+
| July      |
+-----------+
| August    |
+-----------+

此订单将在下个月更改。抱歉，如果重复，我不知道要搜索的关键字是什么。

Answer 1

您可以使用monthname()获取日期的月份名称，并使用date_add()从日期中减去月份。也就是说，您可以使用UNION ALL和无表SELECT来获取月的名称来构建查询，以获得所需的结果。

SELECT monthname(date_add(curdate(), interval -11 month))
UNION ALL
SELECT monthname(date_add(curdate(), interval -10 month))
...
UNION ALL
SELECT monthname(date_add(curdate(), interval -1 month))
UNION ALL
SELECT monthname(curdate());

编辑：

要使其更具动态性，您一次可以创建一个数字表。

CREATE TABLE integers
             (i integer);
INSERT INTO integers
            (i)
            VALUES ...
                   (-11),
                   (-10),
                   ...
                   (-1),
                   (0),
                   ...;

然后您可以从该表中选择所需的范围，以建立月份列表。

SELECT monthname(date_add(curdate(), interval i month))
       FROM integers
       WHERE i >= -11
             AND i <= 0
       ORDER BY i;

Answer 2

使用UNION ALL即时创建月份行，或创建表并在其中插入记录。夫妇月份名称和月份编号。使用数字进行排序。如果要从下个月开始，请与当前月份进行比较：

select name
from
(
  select 1 as num, monthname('2000-01-01') as name
  union all
  select 2 as num, monthname('2000-02-01') as name
  union all
  select 3 as num, monthname('2000-03-01') as name
  union all
  select 4 as num, monthname('2000-04-01') as name
  union all
  select 5 as num, monthname('2000-05-01') as name
  union all
  select 6 as num, monthname('2000-06-01') as name
  union all
  select 7 as num, monthname('2000-07-01') as name
  union all
  select 8 as num, monthname('2000-08-01') as name
  union all
  select 9 as num, monthname('2000-09-01') as name
  union all
  select 10 as num, monthname('2000-10-01') as name
  union all
  select 11 as num, monthname('2000-11-01') as name
  union all
  select 12 as num, monthname('2000-12-01') as name
) months
order by num <= month(current_date), num;

上个月的演示：http://rextester.com/NOYU32731

（这将根据数据库中的语言设置为您提供月份名称。因此，使用此查询时，法国的男孩将以与西班牙的女孩相同的语言查看月份名称。）

MySQL选择月份从当前时间减少

2 个答案: