嗨,我正在尝试使用以下链接中的sql解决问题
https://www.hackerrank.com/challenges/15-days-of-learning-sql/problem
我编写了以下sql查询,并得到了不正确的result.please哪里出错了请
SELECT s.submission_date,COUNT(DISTINCT(s.hacker_id)),s1.hacker_id, h.name
FROM Hackers h INNER JOIN Submissions s ON (h.hacker_id = s.hacker_id)
INNER JOIN Submissions s1 ON s1.hacker_id = s.hacker_id
Where s1.hacker_id = (
SELECT w.hacker_id from
(
SELECT hacker_id, COUNT(hacker_id)from Submissions s
GROUP BY s.submission_date,hacker_id
ORDER BY COUNT(hacker_id) desc, hacker_id ASC
limit 1
) w
)
GROUP BY s.submission_date,s1.hacker_id,h.name
ORDER BY s.submission_date ASC;
实际输出为
2016-03-03 1 80682 Deborah
2016-03-04 1 80682 Deborah
2016-03-07 1 80682 Deborah
2016-03-14 1 80682 Deborah
示例输出为
2016-03-01 4 20703 Angela
2016-03-02 2 79722 Michael
2016-03-03 2 20703 Angela
2016-03-04 2 20703 Angela
如果可能,请建议使用相同代码而不是新代码进行修改。 谢谢