Question

所以今天我遇到了一个问题，即@Formula无法正常工作。让我们说：

数据库

year |  X  |  Y 
-----+-----+-----
2010 |  A  |  10
2011 |  A  |  20
2011 |  B  |  99
2009 |  C  |  30
2010 |  C  |  40

我想获得最高的“ Y”年份并按“ X”分组，所以我编写了这样的查询

SELECT year
FROM (SELECT
        year,
        MAX(y) OVER (PARTITION BY x ) max_y
      FROM TableB) q
WHERE year = '2011' and x = 'A';

所以结果是

year |
-----+
2011 |

然后我想在实体中使用它，所以我用@Formula创建实体

@Formula("(SELECT year FROM (SELECT b.year, MAX(b.y) OVER(PARTITION BY b.x) max_y FROM TableB b) q WHERE year = '2011' AND x = 'A')")
private String yearWithHighestScore;

但是Hibernate会处理：

(select entity0_.year as year1_8_ 
from (select b.year as name, max(b.y) over(partition by b.year) entity0_.max_y from TableB b) entity0_.q 
where entity0_.year=? and entity0_.x=?) as formula0_1_

您看到Hibernate将其转换为“ entity0_.max_y”，这是不正确的，因为max_y不是表TableB的列；它只是计算列的别名

我的问题：我们可以通过任何方式告诉Hibernate这是列的别名，而不是列名本身吗？

谢谢

Answer 1

以'_'开头的别名别名：

@Formula("(SELECT year FROM (SELECT b.year, MAX(b.y) OVER(PARTITION BY b.x) _max_y FROM TableB b) _q WHERE year = '2011' AND x = 'A')")

如何在@Formula中使用别名

1 个答案: