Question

我对数组过滤有疑问。

假设我有两个数组：

var names = ["john", "sarah", "dennis"];
var emails = ["john.doe@gmail.com", "william.iron@gmail.com", "bruce.lee@example.com"];

现在哇，如果名称出现在电子邮件中，我可以比较这些数据并删除它吗？

因此，我应该得到第三个数组，而没有 john.doe@gmail.com ：

var results = ["william.iron@gmail.com","bruce.lee@example.com"];

感谢帮助。

Answer 1

您可以过滤emails并检查names电子邮件中是否包含姓名。

var names = ["john", "sarah", "dennis"],
    emails = ["john.doe@gmail.com", "william.iron@gmail.com", "bruce.lee@example.com"],
    result = emails.filter(email => !names.some(name => email.includes(name)));

console.log(result);

使用正则表达式进行检查的另一种方法。

var names = ["john", "sarah", "dennis"],
    regexp = new RegExp(names.join('|'), 'i'),
    emails = ["john.doe@gmail.com", "william.iron@gmail.com", "bruce.lee@example.com"],
    result = emails.filter(email => !regexp.test(email));

console.log(result);

Answer 2

您可以尝试使用filter：

var names = ["john", "sarah", "dennis"];
var emails = ["john.doe@gmail.com", "william.iron@gmail.com", "bruce.lee@example.com"];

var result = emails.filter(email => !names.find(name => email.includes(name)));

console.log(result);

Answer 3

您可以结合使用Array.filter()和Array.find()：

var names = ["john", "sarah", "dennis"];
var emails = ["john.doe@gmail.com", "william.iron@gmail.com", "bruce.lee@example.com"];
var res = emails.filter(email => !names.find(name => email.includes(name)));
console.log(res);

如果您还担心IE浏览器，请使用简单的函数声明，而不要使用includes()，而应使用indexOf()：

var names = ["john", "sarah", "dennis"];
var emails = ["john.doe@gmail.com", "william.iron@gmail.com", "bruce.lee@example.com"];
var res = emails.filter(function(email) {
  return !names.find(function(name) {
     return (email.indexOf(name) !== -1);
  });
})
console.log(res);

Answer 4

使用array.prototype.filter，array.prototype.some和string.prototype.includes：

var names = ["john", "sarah", "dennis"];
var emails = ["john.doe@gmail.com", "william.iron@gmail.com", "bruce.lee@example.com"];
var res = emails.filter(email => !names.some(name => email.includes(name)));

console.log(res);

Answer 5

您可以尝试

var names = ["john", "sarah", "dennis"];
var emails = ["john.doe@gmail.com", "william.iron@gmail.com", "bruce.lee@example.com"];

const result = emails.filter(email => { 
  let nameInMail = true
  
  names.forEach(name => {
    if (!nameInMail) {
      return
    }

    nameInMail = !(email.indexOf(name) >= 0)  
  })
  
  return nameInMail
})

console.log(result)

编辑：其他人的回答比我的还好哈哈使用.some()看起来是最好的方法

从其他数组删除数组过滤器中的记录

5 个答案: