我将Spring Boot用作Web服务器,有时想响应[HTTP / 1.1 403 XXX]。
我尝试将ResponseEntity
与@ResponseStatus
和response.sendError(403, "XXX")
一起使用,但我嗅探到数据包发现Web服务器仅响应[HTTP / 1.1 403]
CURL示例:
[root@localhost ~]# curl -v 192.168.12.36:8080/test
* About to connect() to 192.168.12.36 port 8080 (#0)
* Trying 192.168.12.36...
* Connected to 192.168.12.36 (192.168.12.36) port 8080 (#0)
> GET /test HTTP/1.1
> User-Agent: curl/7.29.0
> Host: 192.168.12.36:8080
> Accept: */*
>
< HTTP/1.1 403
< X-Content-Type-Options: nosniff
< X-XSS-Protection: 1; mode=block
< Cache-Control: no-cache, no-store, max-age=0, must-revalidate
< Pragma: no-cache
< Expires: 0
< X-Frame-Options: DENY
< Content-Type: application/json;charset=UTF-8
< Transfer-Encoding: chunked
< Date: Thu, 09 Aug 2018 08:26:37 GMT
<
* Connection #0 to host 192.168.12.36 left intact
我需要的答复是:
< HTTP/1.1 403 XXX
< X-Content-Type-Options: nosniff
< X-XSS-Protection: 1; mode=block
< Cache-Control: no-cache, no-store, max-age=0, must-revalidate
< Pragma: no-cache
...
如何在HTTP状态代码后添加自定义消息?
答案 0 :(得分:2)
您可能希望HTTP响应的主体包含一条消息,您可以将其与任何其他信息一起解析。
状态码(在响应中)上的HTTP状态消息可以是您想要的任何内容,并且不会影响任何客户端。 HTTP客户端通常会忽略消息文本。
这是另一种选择。创建一个接受状态码和消息的通用异常。然后创建一个异常处理程序。使用异常处理程序从异常中检索信息,然后返回到服务的调用者。
http://javaninja.net/2016/06/throwing-exceptions-messages-spring-mvc-controller/
public class ResourceException extends RuntimeException {
private HttpStatus httpStatus = HttpStatus.INTERNAL_SERVER_ERROR;
public HttpStatus getHttpStatus() {
return httpStatus;
}
/**
* Constructs a new runtime exception with the specified detail message.
* The cause is not initialized, and may subsequently be initialized by a
* call to {@link #initCause}.
* @param message the detail message. The detail message is saved for later retrieval by the {@link #getMessage()}
* method.
*/
public ResourceException(HttpStatus httpStatus, String message) {
super(message);
this.httpStatus = httpStatus;
}
}
然后使用异常处理程序检索信息并将其返回给服务调用者。
@ControllerAdvice
public class ExceptionHandlerAdvice {
@ExceptionHandler(ResourceException.class)
public ResponseEntity handleException(ResourceException e) {
// log exception
return ResponseEntity.status(e.getHttpStatus()).body(e.getMessage());
}
}
然后在需要时创建一个例外。
throw new ResourceException(HttpStatus.NOT_FOUND, "We were unable to find the specified resource.");
答案 1 :(得分:1)
您在问题中没有这么说,但我想您正在使用Tomcat。默认情况下,Tomcat仅发送状态代码,不发送原因短语。原因短语是HTTP规范的可选部分,因此我不建议依赖它来发送。
如果您真的要依赖自定义原因短语,而不是像其他答案所建议的那样使用响应正文,则必须配置Tomcat发送原因短语(仅Tomcat 8.5支持)切换到另一个容器。对于Spring Boot支持的嵌入式servlet容器,Jetty和Undertow都将发送原因短语。
下面是一个小示例,该示例将Tomcat配置为既发送原因短语又启用自定义短语:
package sample.tomcat;
import javax.servlet.http.HttpServletResponse;
import org.apache.coyote.AbstractProtocol;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.boot.context.embedded.EmbeddedServletContainerCustomizer;
import org.springframework.boot.context.embedded.tomcat.TomcatEmbeddedServletContainerFactory;
import org.springframework.context.annotation.Bean;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.GetMapping;
@SpringBootApplication
public class SampleTomcatApplication {
@Bean
public EmbeddedServletContainerCustomizer tomcatCustomizer() {
return (container) -> {
if (container instanceof TomcatEmbeddedServletContainerFactory) {
((TomcatEmbeddedServletContainerFactory) container)
.addConnectorCustomizers((connector) -> {
((AbstractProtocol<?>) connector.getProtocolHandler())
.setSendReasonPhrase(true);
});
}
};
}
public static void main(String[] args) throws Exception {
System.setProperty("org.apache.coyote.USE_CUSTOM_STATUS_MSG_IN_HEADER", "true");
SpringApplication.run(SampleTomcatApplication.class, args);
}
}
@Controller
class SampleController {
@GetMapping("/")
public void customReasonPhrase(HttpServletResponse response) throws Exception {
response.setStatus(503, "Custom");
}
}
答案 2 :(得分:0)
您可以在@ResponseStatus
注释中设置原因:
@ResponseStatus(value = HttpStatus.FORBIDDEN, reason="You custom reason")