Question

我创建了一个简单的密码生成器，它也可以进行强度检查。但是，如果它无法生成足够强的密码，我将很难决定如何处理。此时，它仅显示创建失败消息。

如果创建的密码强度不够，我应该定义密码创建规则还是只是重新启动该功能？任何意见，建议或线索，不胜感激。谢谢。

代码可以在下面找到。

'use strict'; 


let generatePassword = function(passwordLength = 10) {

  let alphabetString = "QWERTYUIOPASDFGHJKLZXCVBNMqwertyuiopasdfghjklzxcvbnm1234567890-_=+[]{}!@#$%^&*();:'|\,<.>/?`",
  alphabet = alphabetString.split("",),
  passwordArray = [],

  getRandomSymbol = function() {
    return alphabet[Math.floor(Math.random()*alphabet.length)]
  };

  for (let i = 0; i < passwordLength; i++) {
    passwordArray.push(getRandomSymbol());
  } 

  let password = passwordArray.join(""),
  passwordStrengthCheck = new RegExp("^(?=.*[a-z])(?=.*[A-Z])(?=.*[0-9])(?=.*[!@#\$%\^&\*])(?=.{8,})");

  if (password.match(passwordStrengthCheck)) {
    return console.log(`Your password is: ${password}`);
  } else {
    console.log("Failed to generate a strong enough password");
  }
}


// Function call sample:

generatePassword();

Answer 1

要确保您的密码在所有组中至少包含一个符号，请执行以下操作：

从每个组中随机抽取一个字符（1个大写字母，1个小写字母，1个数字...）
从all拾取休息字符
随机挑选字符

代码：

let generatePassword = function(passwordLength = 10) {

  let capitals = "QWERTYUIOPASDFGHJKLZXCVBNM";
  let small = "qwertyuiopasdfghjklzxcvbnm";
  let digits = "1234567890";
  let symbols = "-_=+[]{}!@#$%^&*();:'|\,<.>/?`",
  let all = capitals + small + digits + symbols;


  getRandomSymbol = function(sourceString) {
    return sourceString[Math.floor(Math.random()*sourceString.length)]
  };


  alphabet = alphabetString.split("",),
  passwordArray = [],

  passwordArray.push(getRandomSymbol(capitals));
  passwordArray.push(getRandomSymbol(small));
  passwordArray.push(getRandomSymbol(digits));
  passwordArray.push(getRandomSymbol(symbols));



  for (let i = 0; i < passwordLength - 4; i++) {
    passwordArray.push(getRandomSymbol(all));
  } 


  shuffle = function (a) {
    for (let i = a.length - 1; i > 0; i--) {
        const j = Math.floor(Math.random() * (i + 1));
        [a[i], a[j]] = [a[j], a[i]];
    }
    return a;
  }

  let password = shuffle(passwordArray).join(""),

  passwordStrengthCheck = new RegExp("^(?=.*[a-z])(?=.*[A-Z])(?=.*[0-9])(?=.*[!@#\$%\^&\*])(?=.{8,})");

  if (password.match(passwordStrengthCheck)) {
    return console.log(`Your password is: ${password}`);
  } else {
    console.log("Failed to generate a strong enough password");
  }
}

密码生成器，如何使其返回足够强的密码

1 个答案: