我想在通知到达时从FirebaseMessagingService重新加载WebView,该视图位于MainActivity中,并点击通知。
到目前为止,这是我的代码。
我拥有的 onMessageReceived 方法中的FirebaseMessagingService.java
if(MainActivity.isAppRunning){
Delegate.theMainActivity.onNotificationRefresh();
}
Delegate.java
package ###@@##@@;
public class Delegate {
static MainActivity theMainActivity;
}
在我的 MainActivity 中,我正在尝试调用此方法
public void onNotificationRefresh() {
webView.loadUrl("www.google.com");
}
现在,每当我收到通知而不是调用重新加载应用程序崩溃时,就会崩溃。
错误日志
FATAL EXCEPTION: pool-3-thread-1
Process: ###@@##@@, PID: 11092
java.lang.RuntimeException: java.lang.Throwable: A WebView method was called on thread 'pool-3-thread-1'. All WebView methods must be called on the same thread. (Expected Looper Looper (main, tid 1) {e88a3d1} called on null, FYI main Looper is Looper (main, tid 1) {e88a3d1})
at android.webkit.WebView.checkThread(WebView.java:2588)
at android.webkit.WebView.loadUrl(WebView.java:1005)
at com.###@@##@@.MainActivity.onNotificationRefresh(MainActivity.java:293)
at com.###@@##@@.MyFirebaseMessagingService.onMessageReceived(MyFirebaseMessagingService.java:88)
at com.google.firebase.messaging.FirebaseMessagingService.handleIntent(Unknown Source)
at com.google.firebase.iid.zzc.run(Unknown Source)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1133)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:607)
at java.lang.Thread.run(Thread.java:761)
答案 0 :(得分:2)
尝试使用此方法可以使用 BroadcastReceiver
示例代码
public class MyFirebaseMessagingService extends FirebaseMessagingService {
@Override
public void onMessageReceived(RemoteMessage remoteMessage) {
super.onMessageReceived(remoteMessage);
Log.e("NOTIFICATION_DATA", remoteMessage.getData() + "");
Intent new_intent = new Intent();
Bundle bundle = new Bundle();// use bundle if you want to pass data
bundle.putString("msgBody", remoteMessage.getData().toString());
new_intent.putExtra("msg", bundle);
new_intent.setAction("ACTION_ACTIVITY");
sendBroadcast(new_intent);
}
}
在这样的活动中使用>
public class MyActivity extends AppCompatActivity {
WebView webView;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_my);
}
@Override
protected void onResume() {
super.onResume();
// registering BroadcastReceiver
if (activityReceiver != null) {
IntentFilter intentFilter = new IntentFilter("ACTION_ACTIVITY");
registerReceiver(activityReceiver, intentFilter);
}
}
@Override
protected void onPause() {
super.onPause();
LocalBroadcastManager.getInstance(this).unregisterReceiver(activityReceiver);
}
private BroadcastReceiver activityReceiver = new BroadcastReceiver() {
@Override
public void onReceive(Context context, Intent intent) {
// reload your webview here
webView.loadUrl("https://stackoverflow.com/users/7666442/nilesh-rathod?tab=profile");
}
};
}
答案 1 :(得分:0)
您必须从UI线程调用webView.loadUrl()
:
public void onNotificationRefresh() {
runOnUiThread(new Runnable() {
@Override
public void run() {
this.webView.loadUrl("www.google.com");
}
});
}
希望会有所帮助,干杯