我正在尝试进行分析,以显示两件事。
十分之一(或百分位数)的客户及其收入,因此我可以看到10%的客户数量产生的收入最高。
收入的十分位数:有多少客户产生了10%的收入。
select yeardate, decile, sum(revenue) as revenue, count(distinct(customername)) as cust_count
from
(
select yeardate,
customername,
ntile(10) over (order by sum(revenue) ) as decile,
sum(revenue) as revenue
from
(select
year(DateStamp) as yeardate ,
customername,
sum(Sell) as revenue
from MarginListView
where reporttype = 'Invoice' and sell >0 and year(datestamp) = 2018
group by year(DateStamp), customername) d
group by yeardate, CustomerName) c
group by yeardate, decile
order by 1,2
我可以得到客户数量的十进制,但是收入却没有。
使用MS SQL服务器-感激任何帮助。
答案 0 :(得分:0)
要获取产生收入10%的客户数量,请从累计收入开始:
select customername, sum(sell) as revenue,
sum(sum(sell)) over (order by sum(sell) desc) as running_revenue
from MarginListView
where reporttype = 'Invoice' and sell > 0 and
year(datestamp) = 2018
group by customername;
要获取占10%的数字:
select count(*)
from (select customername, sum(sell) as revenue,
sum(sum(sell)) over (order by sum(sell) desc) as running_revenue,
sum(sum(sell)) over () as total_revenue
from MarginListView
where reporttype = 'Invoice' and sell > 0 and
year(datestamp) = 2018
group by customername
) c
where running_revenue - revenue >= 0.1 * total_revenue;
答案 1 :(得分:0)
戈登-谢谢您的帮助。...确实的确使我朝着需要的方向前进。
我到此结束...
select
yeardate, customername,
sell,
cast((round(sum(sum(revenue_sub_tot)) over (order by sum(revenue_sub_tot) asc),2,2)) as decimal (2,2)) as revenue_percentiles,
cast((round(sum(sum(revenue_sub_tot)) over (order by sum(revenue_sub_tot) asc),1,1)) as decimal (2,2)) as revenue_deciles
from (select year(datestamp) as yeardate,
customername,
sum(sell) as sell,
sum(sell)/sum(sum(sell)) over () as revenue_sub_tot
from MarginListView
where reporttype = 'Invoice' and sell > 0
group by year(datestamp), customername
) c
group by yeardate, customername, sell
order by 1,3