Question

我遇到了一个我不太确定如何正确重新格式化的问题。以下是控制器功能的相关部分：

$paidQuery = DB::table('shipments')
            ->leftJoin('customers', 'shipments.bill_to', '=', 'customers.id')
            ->leftJoin('customer_addresses', 'shipments.billerLocation', '=', 'customer_addresses.id')
            ->leftJoin('payments_distributions','shipments.id','=','payments_distributions.shipment_id')
            ->select('shipments.*', 'customers.customer_name','customer_addresses.billingMethod',DB::raw('COALESCE(sum(payments_distributions.amount),0) AS paid')); 
        $paidQuery->where('shipments.shipment_origin', 1);
        $paidQuery->where('shipments.balance', '<', 'paid')
                          ->where('shipments.balance','>', 0)
                          ->whereNotIn('shipments.shipment_billing_status', [2,3,5]);
        if(!empty($_GET['startDate']) || !empty($_GET['endDate'])){
            $paidQuery->where(function($query) {
                if(empty($_GET['startDate'])){
                    $startDate = Carbon::create(1900, 1, 1, 0, 0, 0);
                } else {
                    $startDate = $_GET['startDate'];
                }

                if(empty($_GET['endDate'])){
                    $endDate = Carbon::now();
                } else {
                    $endDate = $_GET['endDate'];
                }

                return $query->whereBetween('date', [$startDate, $endDate])
                    ->orWhereNull('date');

            });
        }

        $paidQuery->whereNull('shipments.deleted_at')
        ->orderBy('shipments.pro_number', 'DESC')
        ->groupBy('shipments.id')
        ->limit(100);

现在，如您在上面看到的，有一个select语句（第5行），最后是一个别名。这里仅作为如何返回我获取的数据的示例。我已经用它来验证什么是行和什么行不通，并且该特定行是否有效，该行不起作用的部分是此行：

$paidQuery->where('shipments.balance', '<', 'paid')

从记录ID相同的amount表中获取所有payments_distributions的和（或零（0））的正确方法是什么？

我一直在四处寻找，找不到合适的示例，但可以确定搜索词或措辞更有可能。谢谢。

Answer 1

在MySQL中，不可能在同一级别的where子句中使用select子句中定义的别名。但是，MySQL重载了HAVING运算符以允许使用别名，因此以下内容应在此处起作用：

$paidQuery = DB::table('shipments')
        ->leftJoin('customers', 'shipments.bill_to', '=', 'customers.id')
        ->leftJoin('customer_addresses', 'shipments.billerLocation', '=', 'customer_addresses.id')
        ->leftJoin('payments_distributions','shipments.id','=','payments_distributions.shipment_id')
        ->select('shipments.*', 'customers.customer_name','customer_addresses.billingMethod',DB::raw('COALESCE(sum(payments_distributions.amount),0) AS paid')); 
    $paidQuery->where('shipments.shipment_origin', 1);
    $paidQuery->having('shipments.balance', '<', 'paid');
    $paidQuery->where('shipments.balance', '>', 0)
    $paidQuery->whereNotIn('shipments.shipment_billing_status', [2,3,5]);

在这里要明确，我建议您使用以下原始MySQL：

HAVING paid > shipments.balance

正确格式化带子句的子句的正确方法-Laravel

1 个答案: