Question

您好，我正在尝试从txt文件中提取所有数据：

[2018-07-10 15:04:11] USER INPUT "hello"
[2018-07-10 15:04:12] SYSTEM RESPONSE: "Hello! How are you doing today"
[2018-07-10 15:04:42] USER INPUT "I am doing good thank you"
[2018-07-10 15:04:42] SYSTEM RESPONSE: "Good to know"

以一种方式，我只将列表中的双引号中的数据包含在内

["hello","Hello! How are you doing today","I am doing good thank you","Good to know"]

我正在尝试使用

corpus_raw = ""
for log_filename in log_filenames:
    print("Reading '{0}'...".format(log_filename))
    with codecs.open(log_filename, "rb", encoding='utf-8', errors='ignore') as log_file:

        corpus_raw += log_file.read()
    corpus_raw= re.findall(r'\[(.*?)\]\s+', corpus_raw)
    print("Corpus is now {0} characters long".format(len(corpus_raw)))
    print()

但是我无法获得任何结果。任何建议将有所帮助！谢谢

Answer 1

您可以使用.*?：

import re
contents = [re.findall('"(.*?)"', i.strip('\n'))[0] for i in open('filename.txt')]

输出：

['hello', 'Hello! How are you doing today', 'I am doing good thank you', 'Good to know']

Answer 2

您可以简单地将corpus_raw除以"并获得列表中的所有其他项目：

corpus_raw = ""
for log_filename in log_filenames:
    print("Reading '{0}'...".format(log_filename))
    with codecs.open(log_filename, "rb", encoding='utf-8', errors='ignore') as log_file:

        corpus_raw += log_file.read()
    print("Corpus is now {0} characters long".format(len(corpus_raw)))
    print()
corpus_raw = corpus_raw.split('"')[1::2]

corpus_raw将变为（鉴于您的示例输入）：

['hello', 'Hello! How are you doing today', 'I am doing good thank you', 'Good to know']

Answer 3

使用cut：

$ cut -d'"' -f2 < so.txt
hello
Hello! How are you doing today
I am doing good thank you
Good to know

提取所有引号内的数据并列出

3 个答案: