Question

我有一些要解析为pojo的json

import builtins
import io
import os
import pytest
import spam


def patch_open(open_func, files):
    def open_patched(path, mode='r', buffering=-1, encoding=None, 
                    errors=None, newline=None, closefd=True,
                    opener=None):
        if 'w' in mode and not os.path.isfile(path):
            files.append(path)
        return open_func(path, mode=mode, buffering=buffering, 
                         encoding=encoding, errors=errors,
                         newline=newline, closefd=closefd, 
                         opener=opener)
    return open_patched


@pytest.fixture(autouse=True)
def cleanup_files(monkeypatch):
    files = []
    monkeypatch.setattr(builtins, 'open', patch_open(builtins.open, files))
    monkeypatch.setattr(io, 'open', patch_open(io.open, files))
    yield
    for file in files:
        os.remove(file)


def test_plain_write():
    assert spam.plain_write() is None


def test_pathlib_write():
    assert spam.pathlib_write() is None


def test_pathlib_write_text():
    assert spam.pathlib_write_text() is None


def test_pathlib_write_bytes():
    assert spam.pathlib_write_bytes() is None


def test_numpy_save():
    assert spam.numpy_save() is None


def test_numpy_savetxt():
    assert spam.numpy_savetxt() is None

这里123是动态的数字键，有人可以告诉我如何创建处理该动态键的pojo

Answer 1

一个问题：此动态密钥是否不需要转换为pojo？

如何在Java中将动态JSON键映射到对象以进行发布请求

1 个答案: