Question

我有这个SQL：

SELECT COUNT(*) as "With Gold"  FROM user_accounts_gold WHERE level = 6
UNION
SELECT COUNT(*) as "No Gold"    FROM user_accounts_bronze WHERE level = 6

目前输出：

| With Gold |
-------------
| 17734     |
| 2388      |

有没有办法像这样输出：

| With Gold | No Gold |
----------------------
| 17734     | 2388    |

谢谢

Answer 1

改为使用select * from (SELECT COUNT(*) as "With Gold" FROM user_accounts_gold WHERE level = 6) ug CROSS JOIN (SELECT COUNT(*) as "No Gold" FROM user_accounts_bronze WHERE level = 6) ub：

for

Answer 2

您可以在select子查询中完成此操作的另一种方式

SELECT (SELECT COUNT(*) as "With Gold"  FROM user_accounts_gold WHERE level = 6),
       (SELECT COUNT(*) as "No Gold"    FROM user_accounts_bronze WHERE level = 6)

Oracle

SELECT (SELECT COUNT(*) as "With Gold"  FROM user_accounts_gold WHERE level = 6),
       (SELECT COUNT(*) as "No Gold"    FROM user_accounts_bronze WHERE level = 6)
FROM dual

或者您可以通过条件汇总函数

SELECT MAX(CASE WHEN  grp = 'With Gold' then val END) as 'With Gold',
       MAX(CASE WHEN  grp = 'No Gold' then val END) as 'No Gold'
FROM (
    SELECT COUNT(*)  val,'With Gold' grp  FROM user_accounts_gold WHERE level = 6
    UNION
    SELECT COUNT(*)  ,'No Gold'    FROM user_accounts_bronze WHERE level = 6
)t
GROUP BY grp

Answer 3

SELECT COUNT(a.level) AS 'With Gold', COUNT(b.level) as 'No Gold' FROM user_accounts_gold a, user_accounts_bronze b

Answer 4

    SELECT SUM("With Gold") AS "With Gold", SUM("No Gold") AS "No Gold" 
    FROM
    (
     SELECT COUNT(*) as "With Gold", 0 AS "No Gold"  FROM user_accounts_gold WHERE level = 6
     UNION
     SELECT  0 AS "With Gold", COUNT(*) as "No Gold"    FROM user_accounts_bronze WHERE level = 6
    )

Answer 5

如前所述，应该只有一个表。因此，为其创建一个视图。如果需要，可以即时进行。然后计数：

select
  sum(metal = 'gold') as "With Gold",
  sum(metal <> 'gold') as "No Gold"
from
(
  select 'gold' as metal, level from user_accounts_gold
  union all
  select 'bronze' as metal, level from user_accounts_bronze
) one_table
where level = 6;

使用永久视图（即CREATE VIEW ...），可以归结为：

select
  sum(metal = 'gold') as "With Gold",
  sum(metal <> 'gold') as "No Gold"
from one_table
where level = 6;

，您也可以从其他查询的视图中受益。

MySQL UNION：如何在两列中获取数据

5 个答案: