Question

将NSData解析为字典时出现随机崩溃。我用下面的代码。

 -(NSArray *)enumDataParser:(NSMutableData *)responseData
    {   
        @try { 
            NSError *error;      
            NSDictionary *jsonDictionary = [NSJSONSerialization JSONObjectWithData:responseData options:kNilOptions error:&error];
        }
        @catch (NSException *exception) {
            [[IFieldServiceCrashLog sharedLog] writeExceptionLogFile:exception];
            [self performCatchOperation:exception];
        }
    }

有时我会收到“ nil”，有时我的应用程序崩溃（Exception not catched）。

我确定responseData不会为零，因为每当发生崩溃时，"error"都不会给我一个原因（错误为零）。

应用程序在方法JSONObjectWithData本身崩溃。我该如何解决这个问题或处理异常情况？

Answer 1

仅JSON反序列化字典或数组，因此您可以检查并查看日志。其他，请参阅选项类型：->枚举NSJSONReadingOptions，例如“ options：NSJSONReadingAllowFragments”

typedef enum NSJSONReadingOptions : NSUInteger {
    NSJSONReadingMutableContainers = (1UL << 0),
    NSJSONReadingMutableLeaves = (1UL << 1),
    NSJSONReadingAllowFragments = (1UL << 2)
} NSJSONReadingOptions;

示例：

NSError *error = nil;

id jsonObject = [NSJSONSerialization JSONObjectWithData:jsonData options:NSJSONReadingAllowFragments error:&error];

if (error != nil) {
    NSLog(@"***** %@", error.localizedDescription);
} else if (jsonObject != nil) {
    NSLog(@"*** JSON Data converted to NSObject!");
    if ([jsonObject isKindOfClass:[NSDictionary class]]) {
        NSDictionary *deserializedDictionary = (NSDictionary *)jsonObject;
        NSLog(@"JSON Obj class: %@", NSStringFromClass([deserializedDictionary class]));
        NSLog(@"*** its Dictionary Object from JSON Data: %@", deserializedDictionary.description);
    } else if ([jsonObject isKindOfClass:[NSArray class]]) {
        NSArray *deserializedArray = (NSArray *)jsonObject;
        NSLog(@"JSON Obj class: %@", NSStringFromClass([deserializedArray class]));
        NSLog(@"*** its Array Object from JSON Data: %@", deserializedArray.description);
    } else {
        NSLog(@"JSON Obj class: %@", NSStringFromClass([jsonObject class]));
        NSLog(@"*** its UNKNOWN Object from JSON Data: %@", jsonObject);
    }
}

无法在JSONObjectWithData iOS中处理异常？

1 个答案: