Question

我正在跟踪JSON字符串

{
   "daily":{
      "1518220800000":174,
      "1518307200000":175,
      "1518393600000":179,
      "1518480000000":181
   },
   "average":{
      "1518220800000":171,
      "1518307200000":171,
      "1518393600000":171,
      "1518480000000":172
   }
}

并且我想使用PHP访问1518220800000对象中的第一个键名daily。

Answer 1

这将满足您的要求：

$jsonstr = '{
   "daily":{
      "1518220800000":174,
      "1518307200000":175,
      "1518393600000":179,
      "1518480000000":181
   },
   "average":{
      "1518220800000":171,
      "1518307200000":171,
      "1518393600000":171,
      "1518480000000":172
   }
}';
$json = json_decode($jsonstr, true);
echo array_keys($json['daily'])[0];

输出：

1518220800000

Answer 2

阅读this，了解如何从嵌套数组中获取数据：

$data = '{
   "daily":{
      "1518220800000":174,
      "1518307200000":175,
      "1518393600000":179,
      "1518480000000":181
   },
   "average":{
      "1518220800000":171,
      "1518307200000":171,
      "1518393600000":171,
      "1518480000000":172
   }
}';

$character = json_decode($data,true);
echo $character[daily][1518220800000];

输出：174

使用json_decode从JSON对象获取密钥名称

2 个答案: