Question

我正在使用Angular2Csv将JSON结果数据导出到CSV。但是它正在导出所有字段。是否可以仅导出特定字段而无需过滤数据？

 exportToCSV = function (dataobj) {
    const options = {
      fieldSeparator: ',',
      quoteStrings: '"',
      decimalseparator: '.',
      showLabels: true,
      showTitle: true,
      headers: Object.keys(dataobj.data[0]),
      // headers: ['API Id', 'RRN', 'Test Case Group', 'Test Case Id', 'Description', 'Institution id']
    };
    new Angular2Csv(dataobj.data, 'My Report', options);
  };

Answer 1

您可以使用filter过滤出标题和数据；

const exportToCSV = function (dataobj) {debugger;
    const ignoreHeaders = ["test1"];
    const options = {
      fieldSeparator: ',',
      quoteStrings: '"',
      decimalseparator: '.',
      showLabels: true,
      showTitle: true,
      headers: Object.keys(dataobj[0]).filter(a=> ignoreHeaders.indexOf(a)===-1),
      // headers: ['API Id', 'RRN', 'Test Case Group', 'Test Case Id', 'Description', 'Institution id']
    };
    var data= dataobj.map(a=>{
      return options.headers.map(b=>{
         return a[b];
      })
    })
    console.log(options.headers)
    console.log(data);
    
    
  };
  
  exportToCSV([{"test1":"1","test2":"2","test3":"3"},{"test1":"1","test2":"2","test3":"3"},{"test1":"1","test2":"2","test3":"3"}]);

Answer 2

您可以创建一个新的对象资源，该资源仅包含要下载的dataobj中的属性=>'API Id'，'RRN'，'Test Case Group'，'Test Case ID'，'Description' ，“机构ID”，然后将值从原始dataobj对象推送到新对象，如下所示：

this.myData=  new Array<dataObjDownload>();
for (let i = 0; i < this.data.length; i++) {

  this.myData.push
  ({aPIId: this.data[i].aPIId,
    rRN: this.data[i].rRN,
    testCaseGroup: this.data[i].testCaseGroup,
    testCaseId: this.data[i].testCaseId,
    description: this.data[i].description,
    Institutionid: this.data[i].Institutionid,
  });
}

使用Angular2Csv仅导出某些字段

2 个答案: