我正在尝试通过Google+ OAuth进行身份验证。为此,我将带护照的js与Google策略结合使用(passport-google-oauth20模块),但是当护照尝试将用户序列化为会话(使用cookie-session)时,我陷入了错误。
登录Google网站后出现错误。
代码:
passport.serializeUser((user, done) => {
console.log('serialize ' + (user.id == undefined ? null : user.id));
console.log(user);
return done(null, (user.id == undefined ? null : user.id));
});
passport.deserializeUser((id, done) => {
console.log('dserialize id ' + id);
db.connect((err, client, don) => {
if (err) throw err
client.query('SELECT * FROM "AppUsers" WHERE "googleId" = $1', [id], (err, res) => {
don();
if (err) {
console.log(err.stack);
} else {
console.log(res.rows[0]);
if (res.rows[0]) {return done(null, res.rows[0]);}
else {return done(null, null);}
}
});
});
});
编辑:
async function checkGoogle(profile) {
const client = await db.connect();
try {
const { rows } = await client.query('SELECT * FROM "AppUsers" WHERE "googleId" = $1', [profile.id]);
let currentUser = rows[0];
console.log(currentUser);
if (currentUser) {
console.log('in db ' + currentUser.id);
console.log(currentUser);
return currentUser;
} else {
const { rows } = await client.query('INSERT INTO "AppUsers" ("googleId") VALUES ($1) RETURNING *', [profile.id]);
let newUser = rows[0];
console.log('not in db ' + newUser.id);
console.log(newUser);
return newUser;
}
} catch (error) {
alert(error);
} finally {
client.release();
}
}
passport.use(
new GoogleStrategy({
// options for google strategy
clientID: keys.google.clientID,
clientSecret: keys.google.clientSecret,
callbackURL: '/auth/google/redirect'
}, (accessToken, refreshToken, profile, done) => {
// check if user already exists in our own db
return done(null, checkGoogle(profile));
})
);
输出: The error screen
请告诉我您是否需要更多信息。
答案 0 :(得分:0)
您需要等待 checkGoogle 函数通过使用async / await返回数据。
passport.use(
new GoogleStrategy({
// options for google strategy
clientID: keys.google.clientID,
clientSecret: keys.google.clientSecret,
callbackURL: '/auth/google/redirect'
}, async (accessToken, refreshToken, profile, done) => {
const user = await checkGoogle(profile);
// check if user already exists in our own db
return done(null, user);
})
);