我试图为2个表创建“关系”：1个雇员到许多专业。 我有POJO
@Entity
public class Employee implements Serializable{
@PrimaryKey(autoGenerate = true)
@ColumnInfo(name = "employee_id")
private int employeeId;
@ColumnInfo(name = "f_name")
private String f_name;
@ColumnInfo(name = "l_name")
private String l_name;
@ColumnInfo(name = "birthday")
private String birthday;
@Ignore
@ColumnInfo(name = "age")
private int age;
@ColumnInfo(name = "avatar_url")
private String avatr_url;
@Ignore
private List<Specialty> specialty;
和专业：
public class Specialty implements Serializable{
@PrimaryKey
@ColumnInfo(name = "specialty_id")
public int specialty_id;
@ColumnInfo(name = "specialty_name")
public String name;
@ColumnInfo(name = "employeeOwner_id")
public int employeeId;
我也创建了联合课程：
public class EmployeeToSpecialty {
@Embedded
public Employee employee;
@Relation(parentColumn = "employee_id", entityColumn = "specialty_id")
public List<Specialty> specialties;
}
然后我得到了错误： 该查询返回ru.alexsuvorov.employee_service.model.EmployeeToSpecialty未使用的某些列[specialty_id，specialty_name，employeeId]。 您可以在字段上使用@ColumnInfo批注指定映射。 ru.alexsuvorov.employee_service.model.EmployeeToSpecialty具有查询未返回的某些字段[employee_id，f_name，l_name，birthday，avatar_url]。如果不应从结果中读取它们，则可以使用@Ignore批注对其进行标记。您可以通过使用@SuppressWarnings（RoomWarnings.CURSOR_MISMATCH）注释该方法来禁止显示此警告。查询返回的列：Specialty_id，specialty_name，employeeId。 ru.alexsuvorov.employee_service.model.EmployeeToSpecialty中的字段：employee_id，f_name，l_name，birthday，avatar_url。
我添加了必要的列和注释，那是什么问题？