我的页面上有一个切换选项,如下所示:
<div class="jumbotron">
<div class="btn-group">
<label class="btn btn-primary" id="singleChoose" ng-model="radioModel" ng-change="toggleMode()" btn-radio="'Single'">Single</label>
<label class="btn btn-primary" id="bulkChoose" ng-model="radioModel" ng-change="toggleMode()" btn-radio="'Bulk'">Bulk</label>
</div>
<form id="singleContentForm" name="singleContentForm">
<div id="singleContent" class="vertical">
<div id="republish_alert_success" role="alert">
<img src="images/DataServicesAdminAppSuccess.png" width="40" height="40" alt="" />
<strong>Success!</strong> Policy republished.
</div>
</div>
</form>
<form id="bulkContentForm" name="bulkContentForm">
<div id="bulkContent" class="horizontal">
<select class="custom-select" ng-model="republishSource" ng-options="choice.name for choice in republishSources"></select>
<div class="col-md-6">
<input id="republishUpload" required="true" type="file" class="form-control" placeholder="Upload republish file" file-model="uploadedRepublishFile" accept=".csv, application/vnd.openxmlformats-officedocument.spreadsheetml.sheet, application/vnd.ms-excel"
/>
</div>
<div aria-label="file upload">
<input id="republish" type="submit" class="btn btn-success" ng-click="doRepublishFile()" value="Republish" />
</div>
</div>
</form>
</div>
我希望在选择指定的div
的切换开关时重新加载div
。
即,当我选择 Single 时,应在渲染之前重新加载 Single 。
有人可以帮我吗?