我们有一个Web应用程序,其中agnular.js中的客户端和java spring中的服务器。我正在研究从客户端下载此日志文件(即logs.tar)的功能。
当前,我们正在使用blob下载。我们的问题是,如果此日志大小变得很大(如大于2GB),则在流式传输时会在应用程序内存上造成负载。所以我想要一种方法来逐块下载大文件,而不需要将整个Blob加载到内存中。请建议出路。
服务器端Java代码-
public ResponseEntity<?> downloadLogs(HttpServletRequest request) {
File file = preferencesService.downloadLogs();
if (file != null) {
FileInputStream inputStream;
try {
inputStream = new FileInputStream(file);
byte[] content = FileCopyUtils.copyToByteArray(inputStream);
String filename = "com-logs.tar";
HttpHeaders responseHeaders = new HttpHeaders();
responseHeaders.add(HttpHeaders.CONTENT_DISPOSITION, "attachment; filename=" + filename);
responseHeaders.add(HttpHeaders.CONTENT_TYPE, "application/octet-stream"
);
return new ResponseEntity<byte[]>(content, responseHeaders, HttpStatus.OK);
} catch (Exception e) {
logger.error("Error while processing log file for download", e);
}
} else {
logger.error("Failed to download logs");
}
return ResponseEntity.badRequest().build();
}
客户端Angular.js代码-
this._service.downloadLogs().subscribe(
success => {
var blb = new Blob([success], { 'type': "application/octet-stream" });
if (window.navigator && window.navigator.msSaveOrOpenBlob) {
window.navigator.msSaveOrOpenBlob(blb, 'logs.tar');
}
else {
var link = document.createElement('a');
link.href = window.URL.createObjectURL(blb);
link.download = "logs.tar";
document.body.appendChild(link);
link.click();
document.body.removeChild(link);
}
});
新服务器端Java代码-
public void downloadLogs(HttpServletResponse resonse) {
File file = preferencesService.downloadLogs(id);
if (file != null) {
try {
resonse.setContentType("application/octet-stream");
resonse.setHeader("Content-Disposition", "attachment;filename=" + file.getName());
BufferedInputStream inStrem = new BufferedInputStream(new FileInputStream(file));
BufferedOutputStream outStream = new BufferedOutputStream(resonse.getOutputStream());
byte[] buffer = new byte[1024];
int bytesRead = 0;
while ((bytesRead = inStrem.read(buffer)) != -1) {
outStream.write(buffer, 0, bytesRead);
}
outStream.flush();
inStrem.close();
}
...
}
答案 0 :(得分:2)
重要的是不要将文件读入内存,而是将流传递给:
public ResponseEntity<?> downloadLogs(HttpServletRequest request) {
File file = preferencesService.downloadLogs();
if (file != null) {
try (InputStream inputStream = Files.newInputStream(file.toPath())) {
InputStreamResource inputStreamResource =
new InputStreamResource(new inputStream);
HttpHeaders responseHeaders = new HttpHeaders();
//responseHeaders.setContentLength(Files.size(file.toPath()));
responseHeaders.add(HttpHeaders.CONTENT_DISPOSITION, "attachment; filename="
+ filename);
responseHeaders.add(HttpHeaders.CONTENT_TYPE, "application/octet-stream");
return new ResponseEntity(inputStreamResource, responseHeaders, HttpStatus.OK);
}
}
...
}
考虑压缩,因为这将大大加快处理速度并减少服务器负载。 应研究分块,设置内容长度,压缩压缩Web过滤器等。