SQL错误文字为我提供了与实际值不同的值

Question

这是导致错误的代码行：

$result = $mysqli->query("SELECT * FROM 'accounts'.'users' WHERE email='$email' AND hash='$hash' AND active='0'") or die($mysqli->error);

这是显示的错误：

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''accounts'.'users' WHERE email='testemail@email.com' AND hash='76dc611d6eba' at line 1

但是，如果我打印哈希值，则会得到“ 76dc611d6ebaafc66cc0879c71b5db5c”这个要搜索的值以及存储在数据库中的值。我不确定是否只是因为出现其他情况而将其缩短为错误消息。

Answer 1

尝试从'（撇号）更改为`（反引号），或者只是从数据库/表名称中删除单引号，因此查询如下所示：

SELECT * FROM `accounts`.`users` WHERE email='$email' AND hash='$hash' AND active='0'

Answer 2

尝试删除数据库和表名周围的引号

$mysqli = new mysqli("localhost", "my_user", "my_password", "world");

if ($mysqli->connect_errno) {
 printf("Connect failed: %s\n", $mysqli->connect_error);
 exit();
}

$result = $mysqli->query("SELECT * FROM accounts.users WHERE email='$email' AND hash='$hash' AND active='0'") or die($mysqli->error);