Question

我正在尝试查找最近7天内的百分比增长，但是我有点卡住了。当前，在我创建的SQL查询中，您可以获取过去7天中新帐户的总数。但是现在，如何改进才能以百分比形式返回结果？

这是到目前为止完成的SQL查询。

谢谢

<ul>
  <li>foo</li>
  <li>bar</li>
  <li>baz</li>
</ul>

Answer 1

您可以创建一个包含两列的临时表，例如“旧计数”和“新计数”。使用从SELECT查询中获得的值填充表。然后，从临时表中检索值以计算百分比差异并删除临时表。

Answer 2

您可以尝试以下方式计算最近7天的计数，然后在7天之前计算所有数字，然后计算百分比

    select max(last7days_count) as last7days_count,
max(before7days_count) as before7days_count,
    ((max(before7days_count)*1.00)/max(last7days_count))*100.00 as percentage from 
        (
        SELECT COUNT(DISTINCT account_type) as last7days_count, 0 as before7days_count
        FROM account
        WHERE date_created > NOW() - INTERVAL 7 DAY

        union all

        SELECT 0 as last7days_count COUNT(DISTINCT account_type) as before7days_count
        FROM account
        WHERE date_created < NOW() - INTERVAL 7 DAY
        ) as T

Answer 3

为了在一个查询中全部运行，您可以考虑下一个查询：

SELECT
  /* Count for previous period. */
  beforeCount,
  /* Count for current period. */
  afterCount,
  /* Simple math, just calculating percentage. */
  (beforeCount * 100) / afterCount AS percent
FROM (
  SELECT
  /* Select count for previous period. */
  (
    SELECT COUNT(DISTINCT account_type)
    FROM account
    WHERE date_created BETWEEN NOW() - INTERVAL 14 DAY AND NOW() - INTERVAL 7 DAY
  ) AS beforeCount,
  /* Select count for current period. */
  (
    SELECT COUNT(DISTINCT account_type)
    FROM account
    WHERE date_created > NOW() - INTERVAL 7 DAY
  ) AS afterCount
) AS tmp

Answer 4

有条件的聚合可能有效。使用CASE仅计算新帐户，使用SELECT count(DISINCT CASE WHEN date_created > NOW() - INTERVAL 7 DAY THEN account_type END) / count(DISTINCT CASE WHEN date_created <= NOW() - INTERVAL 7 DAY THEN account_type END) * 100 increase FROM account;仅计算旧帐户。

Sub EraseTheThings()
    Dim shp As Shape
    For Each shp In ActiveSheet.Shapes
        shp.Delete
    Next
End Sub

Answer 5

使用临时表，您可以像这样：

    create temporary table storeCount IF NOT EXISTS (
        oldCount INT(10) not null,
        newCount INT(10) not null
    );

    insert into percentage (oldCount,newCount) 
    values
    (SELECT COUNT(DISTINCT acc1.account_type)FROM account acc1, SELECT COUNT(DISTINCT acc2.account_type)
        FROM account acc2 WHERE acc2.date_created > NOW() - INTERVAL 7 DAY);

    select ((newCount/oldCount)*100) as percentage from storeCount;

    drop temporary table IF EXISTS storeCount;

Answer 6

假设每个帐户有一行，则不需要distinct。我猜你想要：

SELECT (SUM(date_created >= CURDATE() - INTERVAL 7 DAY) * 100/ 
        SUM(date_created > CURDATE() - INTERVAL 7 DAY)
       ) as percent_increase
FROM account

如何将SQL结果转换为百分比

6 个答案: