我想使用html文件将图像上传到trapi。运行代码时,出现错误:POST http://localhost:1337/upload 500(内部服务器错误)。
$.ajax({
type: 'POST',
url: 'http://localhost:1337/upload',
datatype: 'image/jpeg',
data: JSON.stringify(img),
complete: function(product) {
console.log('Congrats, your product has been successfully created: ', product.description);
},
fail: function(error) {
console.log('An error occurred:', error);
}
});
答案 0 :(得分:2)
从今天开始,您可以使用axios使用以下代码将文件上传到trapi。这是文件输入中输入事件的处理程序。
onInput (files) {
const axios = require('axios')
const STRAPI_BASE_URL = 'http://localhost:1337'
const formData = new FormData()
formData.append('files', files)
formData.append('ref', 'restaurant') // optional, you need it if you want to link the image to an entry
formData.append('refId', 12345) // optional, you need it if you want to link the image to an entry
formData.append('field', 'image') // optional, you need it if you want to link the image to an entry
axios.post(`${STRAPI_BASE_URL}/upload`, formData)
}
我假设您有一个名为restaurant
的集合,其集合的文件类型为image
。
此处的更多信息:https://strapi.io/documentation/v3.x/plugins/upload.html#upload-files
答案 1 :(得分:1)
如我所见,忘记添加multipart / form-data
mimeType: "multipart/form-data"
您可以查看文档here
允许的参数为:
files: The file(s) to upload. The value(s) can be a Buffer or Stream.
path: (optional): The folder where the file(s) will be uploaded to (only supported on strapi-upload-aws-s3 now).
refId: (optional): The ID of the entry which the file(s) will be linked to.
ref: (optional): The name of the model which the file(s) will be linked to.
source: (optional): The name of the plugin where the model is located.
field: (optional): The field of the entry which the file(s) will be precisely linked to.
单个文件请求
curl -X POST -F 'files=@/path/to/pictures/file.jpg' http://localhost:1337/upload
将文件链接到条目
例如,您在名为avatar的用户模型中具有链接图像字段
{
"files": "...", // Buffer or stream of file(s)
"path": "user/avatar", // Uploading folder of file(s).
"refId": "5a993616b8e66660e8baf45c", // User's Id.
"ref": "user", // Model name.
"source": "users-permissions", // Plugin name.
"field": "avatar" // Field name in the User model.
}
答案 2 :(得分:0)
这是在带有 C# 的 Winforms 中使用 RestRequest
的另一种方法:
var client = new RestClient("http://my-strapi-server:1337/upload");
client.Timeout = -1;
var request = new RestRequest(Method.POST);
request.AddFile("files", @"C:\temp\bryan.jpg");
request.AddParameter("ref", "Singer");
request.AddParameter("refId", "605fe0c8sakhasg4c40253a");
request.AddParameter("field", "logo");
IRestResponse response = client.Execute(request);
Console.WriteLine(response.Content);