Question

想要使字母，数字和允许的符号（“ ^”，“ *”，“ $”，“！”，“％”，“＆”，“（”，“）”，“ -“，” _“，” =“，” +“）长10个字符（据说是一个完美的密码），但是不能这样做！这是到目前为止我得到的：

import random
password="##########"
#Pick Length
pwordLen = random.randint(8,24)

lowerConsonants = ("b","c","d","f","g","h","j","k","l","m","n","p","q","r","s","t","v","w","x","y","z")
upperConsonants = ("B","C","D","F","G","H","J","K","L","M","N","P","Q","R","S","T","V","W","X","Y","Z")
lowerVowels = ("a","e","u","o","i")
upperVowels=("A","E","U","O","I")
numbers = ("0","1","2","3","4","5","6","7","8","9")
symbols = ("^","*","$","!","%","&","(",")","-","_","=","+")

#For character 1 of 24
selectType1=random.randint(1,6)
if selectType1==1 or selectType1==2:
    selectIndividual1=random.randint(1,26)
    selectIndividual1=selectIndividual1-1
elif selectType1==3 or selectType1==4:
    selectIndividual1=random.randint(1,5)
    selectIndividual1=selectIndividual1-1
elif selectType1==5:
    selectIndividual1=random.randint(1,10)
    selectIndividual1=selectIndividual1-1
else:
    selectIndividual1=random.randint(1,12)
    selectIndividual1=selectIndividual1-1

if selectType1==1:
    password[0]=lowerConsonants[selectIndividual1]
elif selectType1==2 :
    password[0]=upperConsonants[selectIndividual1]
elif selectType1==3 :
    password[0]=lowerVowels[selectIndividual1]
elif selectType1==4 :
    password[0]=upperVowels[selectIndividual1]
elif selectType1==5 :
    password[0]=numbers[selectIndividual1]
else:
    password[0]=symbols[selectIndividual1]

print(password)

然后我将每个数字的所有'selectIndividual1'和'selectType1'替换为10，然后将这10个字符合并成字符串。

此刻我收到此错误：

Traceback (most recent call last):
File "/Users/_____/Documents/temp5.py", line 34, in <module>
password[0]=lowerVowels[selectIndividual1]
TypeError: 'str' object does not support item assignment

我在Mac上运行Python 3.7.0

Answer 1

带有随机和字符串库：

import string
import random

all_char = string.ascii_letters + string.punctuation + string.digits
password = "".join(random.choice(all_char) for x in range(random.randint(10)))

//Y+QV9dXGSh
//G?|Q5i?0\\c

编辑

字符串集是：

string.letters:
abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ

string.punctuation:
!"#$%&'()*+,-./:;<=>?@[\]^_`{|}~

string.digits:
0123456789

Answer 2

该解决方案如何？

import string
import random
pwd = []
for i in range(10):
    r = random.choice(string.letters + string.punctuation + string.digits)
    pwd.append(r)
print ''.join(pwd)

输出：

xS1]O3_z~I

打印string.letters，string.punctuation和string.digits：

abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ
!"#$%&'()*+,-./:;<=>?@[\]^_`{|}~
0123456789

Answer 3

问题是，如上所述，在python中，不允许编辑str对象。它们是“不变的”。解决此问题的方法是只添加您的单个字符：pass = pass + selected_char（这不会更改pass对象，而是会创建一个全新的字符）。

例如

password = ""
# your char picking logic here
if selectType == 1:
    password += lowerConsonants[selectIndividual]
# the rest of your code

Answer 4

使用random.choice

>>> import random
>>> all_chars = lowerConsonants + upperConsonants + lowerVowels + upperVowels + numbers+ symbols
>>> ''.join([random.choice(all_chars) for i in range(10)])
'W+8yB533$W'

Answer 5

您正在尝试将数组元素保存到String中，因此会出现错误。

更改此：

Array[(With[{x = "member" <> ToString[#]},
    Clear[x];
    Evaluate[Symbol[x]] = list[[#]]]) &, Length[list]]

对此：

password="##########"
#Pick Length
pwordLen = random.randint(8,24)

如何生成随机的，长10个字符的高位字母，低位字母，数字和一些符号序列？

5 个答案: