用python中的单引号替换特殊情况的双引号

Question

我尝试了几次，但是在正则表达式上却失败了。我想将所有双引号替换为单引号，而不是特殊情况。 "[\"sa\"]" become '[\"sa\"]'

输入

"35457680047217","1","425121","2018-07-15 00:00:00.000",,,,"10.0","0",,"0",,"0",,,"0","0","0","0",,"[\"23\"]","[\"20\"]","[\"2\",\"58\"]","[\"0\",\"1\",\"2\",\"3\",\"4\"]","2",,"0",,"2018-07-15 00:00:00.000","2018-07-15 00:00:00.000","22",,,,"3",

输出

'35457680047217','1','425121','2018-07-15 00:00:00.000',,,,'10.0','0',,'0',,'0',,,'0','0','0','0',,'[\"23\"]','[\"20\"]','[\"2\",\"58\"]','[\"0\",\"1\",\"2\",\"3\",\"4\"]','2',,'0',,'2018-07-15 00:00:00.000','2018-07-15 00:00:00.000','22',,,,'3',

Answer 1

您可以使用以下正则表达式：(^|[^\\])"。它寻找双引号（"），其后是字符串的开头或不是\的东西。进行全局匹配，并替换为\1'。

在regex01上的演示

Answer 2

您可以基于逗号将字符串拆分为多个单词，但将[.*]视为一个整体元素，在单词边界处将"替换为"，然后再将单词重新连接起来

>>> s = '"35457680047217","1","425121","2018-07-15 00:00:00.000",,,,"10.0","0",,"0",,"0",,,"0","0","0","0",,"[\"23\"]","[\"20\"]","[\"2\",\"58\"]","[\"0\",\"1\",\"2\",\"3\",\"4\"]","2",,"0",,"2018-07-15 00:00:00.000","2018-07-15 00:00:00.000","22",,,,"3",'
>>> new_s = ','.join(map(lambda w: re.sub('(^")|("$)', "'", w), re.split(r',(?="\[)|(?<!=\]"),', s)))
>>> print(new_s)
'35457680047217','1','425121','2018-07-15 00:00:00.000',,,,'10.0','0',,'0',,'0',,,'0','0','0','0',,'["23"]','["20"]','["2','58"]','["0','1','2','3','4"]','2',,'0',,'2018-07-15 00:00:00.000','2018-07-15 00:00:00.000','22',,,,'3',
>>>