Question

我有一个字符串：

"2\nOur\nstrategy drives \nsustainably higher profits and margins\n\nStrengthening our hubs is a critical foundation to maximize profitability\n\nDriving revenue improvements from all areas of business\n\nImproving efficiency and productivity \n\nGreater accountability and transparency\n"

输出应为：

"2 Our strategy drives sustainably higher profits and margins\nStrengthening our hubs is a critical foundation to maximize profitability\nDriving revenue improvements from all areas of business\nImproving efficiency and productivity \nGreater accountability and transparency "

Answer 1

Pythonic解决方案：

'\n'.join(e.replace('\n', ' ') for e in s.split('\n\n'))

首先，分割出现'\n\n'的字符串，然后在列表的每个元素中用'\n'替换' '，最后，将所有内容与{{1 }}。

另一种解决方案

我将使用一个临时助手字符串，该字符串允许我临时替换双换行，然后用空格替换单个换行符，然后用换行符替换临时助手字符串：

假设您的字符串为'\n'：

Answer 2

创建映射字典：

dct = {'\n\n': '\n', '\n': ' '}

使用 re.sub （此正则表达式的顺序很重要）：

re.sub(r'(\n\n|\n)', lambda x: dct[x.group()], s)

输出：

'2 Our strategy drives  sustainably higher profits and margins\nStrengthening our hubs is a critical foundation to maximize profitability\nDriving revenue improvements from all areas of business\nImproving efficiency and productivity \nGreater accountability and transparency '

对此有一些解释。 Python的正则表达式模块不支持重叠匹配，因此当它匹配\n\n时，它也将不匹配\n，这使您可以在一个步骤中完成两个替换。

Answer 3

使用re.sub：

import re
s = "string\n\n\nwith\n\nmultiple\n\n\nnewlines"
# Replace all multiple newlines with one newline
new_string = re.sub(r'\n+', '\n', s)

用一个空格替换单个换行和单个换行的pythoninc方法是什么？

3 个答案: