我有一个文件,其中包含美国的每个邮政编码以及它们各自的纬度和经度。文件格式为“ ZIP / LAT / LNG \ n”,我将每个值保存到数据库中。因此,我编写了以下代码来测试是否可以正确拆分值:
zip_code_file = open('zipcode.rtf')
for s in zip_code_file.read().split(','):
print(s)
但此打印 “ 00602” “ 18.361945” “ -67.175597 \”
如何从经度中删除该“ \”,以便将其正确保存到数据库中?我尝试了以下操作,但没有成功:
for s in zip_code_file.read():
if s == '\\':
s.replace('\]', '')
print(s)
答案 0 :(得分:0)
执行以下操作:
and(succeeded(), ne(variables['Build.Reason'], 'PullRequest'))
输出:
l=["00602", "18.361945", "-67.175597\\"]
print([i.replace('\\','') for i in l])
答案 1 :(得分:0)
您的代码:
for s in zip_code_file.read(): # ok, you get lines
if s == '\\': # if the whole line is equal to \
s.replace('\]', '') # replace "\]" (???) with ""
print(s)
问题:
str.replace()
确实返回了您不留用的更改字符串,因此将其丢弃解决方案:
with open('zipcode.rtf') as zip_code_file:
lines = zip_code_file.readlines()
lines = [x.strip() for x in lines if x.strip()] # removes whitespaces && empty lines
for l in lines:
try:
zipCode,lat,long = l.split(",") # split on ',' or '/'? your code and Q differ
long = long.rstrip("\\") # remove trailing \
# do smth with zipCode,lat,long
except ValueError as ve:
print("Value error in line: ", l)